{"id":10864,"date":"2021-09-30T14:30:29","date_gmt":"2021-09-30T09:00:29","guid":{"rendered":"https:\/\/python-programs.com\/?p=10864"},"modified":"2021-11-22T18:34:32","modified_gmt":"2021-11-22T13:04:32","slug":"python-program-to-print-1-and-0-in-alternative-rows","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-program-to-print-1-and-0-in-alternative-rows\/","title":{"rendered":"Python Program to Print 1 and 0 in Alternative Rows"},"content":{"rendered":"<p>Grab the opportunity to learn all effective java programming language concepts from basic to advance levels by practicing these <a href=\"https:\/\/python-programs.com\/python-programming-examples-with-output\/\">Java Program Examples with Output<\/a><\/p>\n<p>Given the number of rows and columns, the task is to print 1 and 0 in alternative rows in C, C++, and Python.<\/p>\n<p><strong>Examples:<\/strong><\/p>\n<p><strong>Example1:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>given number of rows =4\r\ngiven number of columns=3<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 \r\n0 0 0 \r\n1 1 1 \r\n0 0 0<\/pre>\n<p><strong>Example2:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>given number of rows =7\r\ngiven number of columns=15<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1<\/pre>\n<h2>Program to Print 1 and 0 in Alternative Rows in C, C++, and Python<\/h2>\n<p>Below are the ways to print 1 and 0 in alternative rows in C, C++, and Python.<\/p>\n<ul>\n<li><a href=\"#Using_For_loop\">Using For loop<\/a><\/li>\n<li><a href=\"#Using_While_loop\">Using While loop<\/a><\/li>\n<\/ul>\n<p>If you look closely at the pattern, you&#8217;ll see that for all odd rows, 1 is printed and for all even rows, 0 is printed. As a<\/p>\n<p>result, before displaying integers inside the inner loop, you must check for even-odd conditions. If the current row is<\/p>\n<p>an odd number, print 1 otherwise, print 0.<\/p>\n<p>The following is a step-by-step description of the logic used to print a 1, 0 number pattern at alternate rows.<\/p>\n<h3 id=\"Using_For_loop\">Method #1: Using For loop<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the number of rows and number of columns as static input.<\/li>\n<li>Store them in two separate variables row numbers and column numbers.<\/li>\n<li>Run an outer loop from 1 to rows to iterate through the rows using For loop.<\/li>\n<li>Iterate through the columns from 1 to cols using another For inner loop.<\/li>\n<li>Before printing any number, we must first check the condition inside the inner loop.<\/li>\n<li>This means that for every odd row, 1 is displayed, and for every even row, 0 is displayed.<\/li>\n<li>We check whether the row is odd or not using the if statement.<\/li>\n<li>If it is true then print 1 else print 0.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>1) Python Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows and number of columns as static input.\r\n# Store them in two separate variables row numbers and column numbers.\r\nrownumbs = 15\r\ncolnumbs = 11\r\n# Run an outer loop from 1 to rows to iterate through the rows using For loop.\r\nfor m in range(1, rownumbs+1):\r\n  # Iterate through the columns from 1 to cols using another For inner loop.\r\n    for n in range(1, colnumbs+1):\r\n      # Before printing any number, we must first check the condition inside the inner loop.\r\n      # This means that for every odd row, 1 is displayed, and for every even row, 0 is displayed.\r\n          # We check whether the row is odd or not using the if statement.\r\n      # If it is true then print 1 else print 0.\r\n        if(m % 2 == 1):\r\n            print('1', end=' ')\r\n        # If it is true then print 1 else print 0.\r\n        else:\r\n            print('0', end=' ')\r\n    print()\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1<\/pre>\n<p><strong>2) C++ Implementation<\/strong><\/p>\n<p>It is the same as the python approach but just the change in syntax.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\nusing namespace std;\r\n\r\nint main()\r\n{\r\n    \/\/ Give the number of rows and number of columns as\r\n    \/\/ static input.\r\n    \/\/ Store them in two separate variables row numbers and\r\n    \/\/ column numbers.\r\n    int rownumbs = 15;\r\n    int colnumbs = 11;\r\n    \/\/ Run an outer loop from 1 to rows to iterate through\r\n    \/\/ the rows using For loop.\r\n    for (int i = 1; i &lt;= rownumbs; i++) {\r\n        \/\/ Iterate through the columns from 1 to cols using\r\n        \/\/ another For inner loop.\r\n        for (int j = 1; j &lt;= colnumbs; j++) {\r\n            \/\/ Before printing any number, we must\r\n            \/\/ first check the condition inside the\r\n            \/\/ inner loop.\r\n            \/\/ This means that for every odd row, 1 is\r\n            \/\/ displayed, and for every even row,\r\n            \/\/ 0 is displayed.\r\n            \/\/ We check whether the row is odd or not using\r\n            \/\/ the if statement.\r\n            \/\/ If it is true then print 1 else print 0.\r\n\r\n            if (i % 2 == 1)\r\n                cout &lt;&lt; \"1 \";\r\n            \/\/ If it is true then print 1 else print 0.\r\n            else\r\n                cout &lt;&lt; \"0 \";\r\n        }\r\n        cout &lt;&lt; endl;\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1<\/pre>\n<p><strong>3) C Implementation<\/strong><\/p>\n<p>It is the same as the python approach but just the change in syntax.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\">#include &lt;stdio.h&gt;\r\n\r\nint main(void)\r\n{\r\n    \/\/ Give the number of rows and number of columns as\r\n    \/\/ static input.\r\n    \/\/ Store them in two separate variables row numbers and\r\n    \/\/ column numbers.\r\n    int rownumbs = 15;\r\n    int colnumbs = 11;\r\n    \/\/ Run an outer loop from 1 to rows to iterate through\r\n    \/\/ the rows using For loop.\r\n    for (int i = 1; i &lt;= rownumbs; i++) {\r\n        \/\/ Iterate through the columns from 1 to cols using\r\n        \/\/ another For inner loop.\r\n        for (int j = 1; j &lt;= colnumbs;\r\n             j++) { \/\/ Before printing any number, we must\r\n            \/\/ first check the condition inside the\r\n            \/\/ inner loop.\r\n            \/\/ This means that for every odd row, 1 is\r\n            \/\/ displayed, and for every even row, 0 is\r\n            \/\/ displayed.\r\n            \/*We check whether the row is odd or not using\r\n              the if statement. If it is true then print 1\r\n              else print 0.*\/\r\n            if (i % 2 == 1)\r\n                printf(\"1 \");\r\n            \/\/ If it is true then print 1 else print 0.\r\n            else\r\n                printf(\"0 \");\r\n        }\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1<\/pre>\n<h3 id=\"Using_While_loop\">Method #2: Using while loop<\/h3>\n<p><strong>1) C Implementation<\/strong><\/p>\n<p>We just iterate till rownumbs and columumbs using a while loop.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"c\">#include &lt;stdio.h&gt;\r\n\r\nint main(void)\r\n{\r\n    \/\/ Give the number of rows and number of columns as\r\n    \/\/ static input.\r\n    \/\/ Store them in two separate variables row numbers and\r\n    \/\/ column numbers.\r\n    int rownumbs = 4;\r\n    int colnumbs = 3;\r\n    \/\/ Run an outer loop from 1 to rows to iterate through\r\n    \/\/ the rows using For loop.\r\n    int temprow = 1;\r\n    while (temprow &lt;= rownumbs) {\r\n        \/\/ Iterate through the columns from 1 to cols using\r\n        \/\/ another For inner loop.\r\n        int tempcol = 1;\r\n        while (tempcol &lt;= colnumbs) { \/\/ Before printing any\r\n                                      \/\/ number, we must\r\n            \/\/ first check the condition inside the\r\n            \/\/ inner loop. This means that for every odd\r\n            \/\/ row, 1 is displayed, and for every even row,\r\n            \/\/ 0 is displayed. # We check whether the row is\r\n            \/\/ odd or not using the if statement. # If it is\r\n            \/\/ true then print 1 else print 0.\r\n            if (temprow % 2 == 1)\r\n                printf(\"1 \");\r\n            \/\/ If it is true then print 1 else print 0.\r\n            else\r\n                printf(\"0 \");\r\n            tempcol++;\r\n        }\r\n        temprow++;\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 \r\n0 0 0 \r\n1 1 1 \r\n0 0 0<\/pre>\n<p><strong>2) C++ Implementation:<\/strong><\/p>\n<p>We just iterate till rownumbs and columumbs using a while loop.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\nusing namespace std;\r\n\r\nint main(void)\r\n{\r\n    \/\/ Give the number of rows and number of columns as\r\n    \/\/ static input.\r\n    \/\/ Store them in two separate variables row numbers and\r\n    \/\/ column numbers.\r\n    int rownumbs = 2;\r\n    int colnumbs = 19;\r\n    \/\/ Run an outer loop from 1 to rows to iterate through\r\n    \/\/ the rows using For loop.\r\n    int temprow = 1;\r\n    while (temprow &lt;= rownumbs) {\r\n        \/\/ Iterate through the columns from 1 to cols using\r\n        \/\/ another For inner loop.\r\n        int tempcol = 1;\r\n        while (tempcol &lt;= colnumbs) { \/\/ Before printing any\r\n                                      \/\/ number, we must\r\n            \/\/ first check the condition inside the\r\n            \/\/ inner loop. This means that for every odd\r\n            \/\/ row, 1 is displayed, and for every even row,\r\n            \/\/ 0 is displayed. # We check whether the row is\r\n            \/\/ odd or not using the if statement. # If it is\r\n            \/\/ true then print 1 else print 0.\r\n            if (temprow % 2 == 1)\r\n                cout &lt;&lt; \"1 \";\r\n            \/\/ If it is true then print 1 else print 0.\r\n            else\r\n                cout &lt;&lt; \"0 \";\r\n            tempcol++;\r\n        }\r\n        temprow++;\r\n        cout &lt;&lt; endl;\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0<\/pre>\n<p><strong>3) Python Implementation<\/strong><\/p>\n<p>We just iterate till rownumbs and columumbs using a while loop.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows and number of columns as static input.\r\n# Store them in two separate variables row numbers and column numbers.\r\nrownumbs = 6\r\ncolnumbs = 11\r\n# Run an outer loop from 1 to rows to iterate through the rows using For loop.\r\ntemprow = 1\r\nwhile(temprow &lt;= rownumbs):\r\n  # Iterate through the columns from 1 to cols using another For inner loop.\r\n    tempcol = 1\r\n    while(tempcol &lt;= colnumbs):\r\n      # Before printing any number, we must first check the condition inside the inner loop.\r\n      # This means that for every odd row, 1 is displayed, and for every even row, 0 is displayed.\r\n      # We check whether the row is odd or not using the if statement.\r\n        if(temprow % 2 == 1):\r\n            print('1', end=' ')\r\n        # If it is true then print 1 else print 0.\r\n        else:\r\n            print('0', end=' ')\r\n        tempcol += 1\r\n    temprow += 1\r\n    print()\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0 \r\n1 1 1 1 1 1 1 1 1 1 1 \r\n0 0 0 0 0 0 0 0 0 0 0<\/pre>\n<p><strong>Related Programs<\/strong>:<\/p>\n<ul>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-1-and-0-in-alternative-columns\/\">python program to print 1 and 0 in alternative columns<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-largest-even-and-largest-odd-number-in-a-list\/\">python program to print largest even and largest odd number in a list<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/program-to-print-collatz-conjecture-for-a-given-number-in-cpp-and-python\/\">program to print collatz conjecture for a given number in cpp and python<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-sum-of-negative-numbers-positive-even-numbers-and-positive-odd-numbers-in-a-list\/\">python program to print sum of negative numbers positive even numbers and positive odd numbers in a list<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-generate-a-dictionary-that-contains-numbers-between-1-and-n-in-the-form-x-xx\/\">python program to generate a dictionary that contains numbers between 1 and n in the form x xx<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-read-a-text-file-and-print-all-the-numbers-present-in-the-text-file\/\">python program to read a text file and print all the numbers present in the text file<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-accept-a-hyphen-separated-sequence-of-words-as-input-and-print-the-words-in-a-hyphen-separated-sequence-after-sorting-them-alphabetically\/\">python program to accept a hyphen separated sequence of words as input and print the words in a hyphen separated sequence after sorting them alphabetically<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Grab the opportunity to learn all effective java programming language concepts from basic to advance levels by practicing these Java Program Examples with Output Given the number of rows and columns, the task is to print 1 and 0 in alternative rows in C, C++, and Python. Examples: Example1: Input: given number of rows =4 &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/python-programs.com\/python-program-to-print-1-and-0-in-alternative-rows\/\"> <span class=\"screen-reader-text\">Python Program to Print 1 and 0 in Alternative Rows<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":7,"featured_media":10877,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","jetpack_publicize_message":"","jetpack_is_tweetstorm":false,"jetpack_publicize_feature_enabled":true},"categories":[19,5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Python Program to Print 1 and 0 in Alternative Rows - Python Programs<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/python-programs.com\/python-program-to-print-1-and-0-in-alternative-rows\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Python Program to Print 1 and 0 in Alternative Rows - Python Programs\" \/>\n<meta property=\"og:description\" content=\"Grab the opportunity to learn all effective java programming language concepts from basic to advance levels by practicing these Java Program Examples with Output Given the number of rows and columns, the task is to print 1 and 0 in alternative rows in C, C++, and Python. 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