{"id":11946,"date":"2021-09-30T14:30:51","date_gmt":"2021-09-30T09:00:51","guid":{"rendered":"https:\/\/python-programs.com\/?p=11946"},"modified":"2021-11-22T18:34:31","modified_gmt":"2021-11-22T13:04:31","slug":"python-program-to-print-diamond-star-pattern","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-program-to-print-diamond-star-pattern\/","title":{"rendered":"Python Program to Print Diamond Star Pattern"},"content":{"rendered":"<p>Are you a job seeker and trying to find simple <a href=\"https:\/\/python-programs.com\/python-programming-examples-with-output\/\">java programs for Interview?<\/a> This would be the right choice for you, just tap on the link and start preparing the java programs covered to crack the interview.<\/p>\n<p>Given the number of rows of the diamond pattern, the task is to print the diamond star pattern in C, C++, and Python<\/p>\n<p><strong>Examples:<\/strong><\/p>\n<p><strong>Example1:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>given number of rows of diamond =5<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">      *\r\n    ***\r\n   *****\r\n  *******\r\n *********\r\n  *******\r\n   *****\r\n    ***\r\n     *<\/pre>\n<p><strong>Example2:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>given number of rows of diamond =7\r\ngiven character to print ='$'<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">          $\r\n        $$$\r\n       $$$$$\r\n     $$$$$$$\r\n   $$$$$$$$$\r\n  $$$$$$$$$$$\r\n$$$$$$$$$$$$$\r\n  $$$$$$$$$$$\r\n    $$$$$$$$$\r\n      $$$$$$$\r\n        $$$$$\r\n         $$$\r\n           $<\/pre>\n<h2>Program to Print Diamond Star Pattern in C, C++, and Python<\/h2>\n<p>Below are the ways to print Diamond Star Pattern in C, C++, and Python.<\/p>\n<ul>\n<li><a href=\"#Using_For_Loop_(Star_Character)\">Using For Loop (Star Character)<\/a><\/li>\n<li><a href=\"#Using_For_Loop_(User_Character)\">Using For Loop (User Character)<\/a><\/li>\n<\/ul>\n<h3 id=\"Using_For_Loop_(Star_Character)\">Method #1: Using For loop (Star Character)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the number of rows of the diamond pattern as static input and store it in a variable.<\/li>\n<li>Loop from 1 to the number of rows using For Loop.<\/li>\n<li>Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 0 to the 2* iterator value &#8211; 1 of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the star character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>Loop from 1 to the number of rows using For loop.<\/li>\n<li>Loop from 1 to iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 1 to 2*(number of rows &#8211; iterator value of the parent for loop) using another For loop(Nested For loop).<\/li>\n<li>Print the star character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>1) Python Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows of the diamond pattern as static input and store it in a variable.\r\n\r\ndiamondrows = 5\r\n# Loop from 1 to the number of rows using For Loop.\r\nfor m in range(1, diamondrows+1):\r\n    # Loop from 1 to the number of rows -iterator value of the parent\r\n    # For loop using another For loop(Nested For loop).\r\n    for n in range(1, diamondrows - m + 1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 0 to the 2* iterator value - 1 of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for l in range(0, (2 * m) - 1):\r\n        # Print the star character\r\n        print('*', end='')\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print()\r\n\r\n# Loop from 1 to the number of rows using For loop.\r\nfor m in range(1, diamondrows):\r\n    # Loop from 1 to iterator value of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for n in range(1, m+1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 1 to 2*(number of rows - iterator value of the parent for loop)\r\n    # using another For loop(Nested For loop).\r\n    for l in range(1, (2 * (diamondrows - m))):\r\n        # Print the star character\r\n        print('*', end='')\r\n\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print()\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">     *\r\n    ***\r\n   *****\r\n  *******\r\n *********\r\n  *******\r\n   *****\r\n    ***\r\n     *<\/pre>\n<p><strong>2) C++ Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\nusing namespace std;\r\n\r\nint main()\r\n{\r\n    \/\/ Give the number of rows of the diamond pattern\r\n    \/\/ as static input and store it in a variable.\r\n\r\n    int diamondrows = 5;\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 0 to the 2 * iterator value- 1 of the\r\n        \/\/ parent For loop using another For loop(Nested For\r\n        \/\/ loop).\r\n        for (int l = 0; l &lt; ((2 * m) - 1); l++) {\r\n            \/\/ Print the star character\r\n            cout &lt;&lt; \"*\";\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n    for (int m = 1; m &lt; diamondrows; m++) {\r\n        \/\/ Loop from 1 to iterator value of the parent For\r\n        \/\/ loop using another For loop(Nested For loop).\r\n        for (int n = 1; n &lt;= m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 1 to 2* (number of rows- iterator value\r\n        \/\/ of the parent for loop) using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * (diamondrows - m)); l++) {\r\n            \/\/ Print the star character\r\n            cout &lt;&lt; \"*\";\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">     *\r\n    ***\r\n   *****\r\n  *******\r\n *********\r\n  *******\r\n   *****\r\n    ***\r\n     *<\/pre>\n<p><strong>3) C Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"c\">#include &lt;stdio.h&gt;\r\n\r\nint main()\r\n{ \/\/ Give the number of rows of the diamond pattern\r\n    \/\/ as static input and store it in a variable.\r\n\r\n    int diamondrows = 5;\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            printf(\" \");\r\n        }\r\n        \/\/ Loop from 0 to the 2 * iterator value- 1 of the\r\n        \/\/ parent For loop using another For loop(Nested For\r\n        \/\/ loop).\r\n        for (int l = 0; l &lt; ((2 * m) - 1); l++) {\r\n            \/\/ Print the star character\r\n            printf(\"*\");\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        printf(\"\\n\");\r\n    }\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n    for (int m = 1; m &lt; diamondrows; m++) {\r\n        \/\/ Loop from 1 to iterator value of the parent For\r\n        \/\/ loop using another For loop(Nested For loop).\r\n        for (int n = 1; n &lt;= m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            printf(\" \");\r\n        }\r\n        \/\/ Loop from 1 to 2* (number of rows- iterator value\r\n        \/\/ of the parent for loop) using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * (diamondrows - m)); l++) {\r\n            \/\/ Print the star character\r\n            printf(\"*\");\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">     *\r\n    ***\r\n   *****\r\n  *******\r\n *********\r\n  *******\r\n   *****\r\n    ***\r\n     *<\/pre>\n<h3 id=\"Using_For_Loop_(User_Character)\">Method #2: Using For loop (User Character)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the number of rows of the diamond pattern as user input and store it in a variable.<\/li>\n<li>Give the character to print as user input and store it in a variable.<\/li>\n<li>Loop from 1 to the number of rows using For Loop.<\/li>\n<li>Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 0 to the 2* iterator value &#8211; 1 of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the given character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>Loop from 1 to the number of rows using For loop.<\/li>\n<li>Loop from 1 to iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 1 to 2*(number of rows &#8211; iterator value of the parent for loop) using another For loop(Nested For loop).<\/li>\n<li>Print the given character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>1) Python Implementation<\/strong><\/p>\n<ul>\n<li>Give the number of rows as user input using int(input()) and store it in a variable.<\/li>\n<li>Give the Character as user input using input() and store it in another variable.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows  as user input using int(input()) and store it in a variable.\r\ndiamondrows = int(input(\r\n    'Enter some random number of rows  = '))\r\n# Give the Character as user input using input() and store it in another variable.\r\ngivencharacter = input('Enter some random character = ')\r\n# Loop from 1 to the number of rows using For Loop.\r\nfor m in range(1, diamondrows+1):\r\n    # Loop from 1 to the number of rows -iterator value of the parent\r\n    # For loop using another For loop(Nested For loop).\r\n    for n in range(1, diamondrows - m + 1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 0 to the 2* iterator value - 1 of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for l in range(0, (2 * m) - 1):\r\n        # Print the given character\r\n        print(givencharacter, end='')\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print()\r\n\r\n# Loop from 1 to the number of rows using For loop.\r\nfor m in range(1, diamondrows):\r\n    # Loop from 1 to iterator value of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for n in range(1, m+1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 1 to 2*(number of rows - iterator value of the parent for loop)\r\n    # using another For loop(Nested For loop).\r\n    for l in range(1, (2 * (diamondrows - m))):\r\n        # Print the given character\r\n        print(givencharacter, end='')\r\n\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print()\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">Enter some random number of rows = 7\r\nEnter some random character = $\r\n          $\r\n        $$$\r\n       $$$$$\r\n     $$$$$$$\r\n   $$$$$$$$$\r\n  $$$$$$$$$$$\r\n$$$$$$$$$$$$$\r\n  $$$$$$$$$$$\r\n    $$$$$$$$$\r\n      $$$$$$$\r\n        $$$$$\r\n         $$$\r\n           $<\/pre>\n<p><strong>2) C++ Implementation<\/strong><\/p>\n<ul>\n<li>Give the number of rows as user input using cin and store it in a variable.<\/li>\n<li>Give the Character as user input using cin and store it in another variable.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\nusing namespace std;\r\n\r\nint main()\r\n{\r\n\r\n    \/\/ Give the number of rows\r\n    \/\/ as user input using cin and store it in a\r\n    \/\/ variable.\r\n    int diamondrows;\r\n    char givencharacter;\r\n    cout &lt;&lt; \"Enter some random number of rows = \" &lt;&lt; endl;\r\n    cin &gt;&gt; diamondrows;\r\n    \/\/ Give the Character as user input using cin and store\r\n    \/\/ it in another variable.\r\n    cout &lt;&lt; \"Enter some random character = \" &lt;&lt; endl;\r\n    cin &gt;&gt; givencharacter;\r\n    cout &lt;&lt; endl;\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 0 to the 2 * iterator value- 1 of the\r\n        \/\/ parent For loop using another For loop(Nested For\r\n        \/\/ loop).\r\n        for (int l = 0; l &lt; ((2 * m) - 1); l++) {\r\n            \/\/ Print the given character\r\n            cout &lt;&lt; givencharacter;\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n    for (int m = 1; m &lt; diamondrows; m++) {\r\n        \/\/ Loop from 1 to iterator value of the parent For\r\n        \/\/ loop using another For loop(Nested For loop).\r\n        for (int n = 1; n &lt;= m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 1 to 2* (number of rows- iterator value\r\n        \/\/ of the parent for loop) using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * (diamondrows - m)); l++) {\r\n            \/\/ Print the  given character\r\n            cout &lt;&lt; givencharacter;\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">Enter some random number of rows = \r\n7\r\nEnter some random character = \r\n$\r\n          $\r\n        $$$\r\n       $$$$$\r\n     $$$$$$$\r\n   $$$$$$$$$\r\n  $$$$$$$$$$$\r\n$$$$$$$$$$$$$\r\n  $$$$$$$$$$$\r\n    $$$$$$$$$\r\n      $$$$$$$\r\n        $$$$$\r\n         $$$\r\n           $<\/pre>\n<p><strong>3) C Implementation<\/strong><\/p>\n<ul>\n<li>Give the number of rows as user input using scanf and store it in a variable.<\/li>\n<li>Give the Character as user input using scanf and store it in another variable.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"c\">#include &lt;stdio.h&gt;\r\n\r\nint main()\r\n{\r\n    \/\/ Give the number of rows\r\n    \/\/  as user input using scanf and store it in a\r\n    \/\/ variable.\r\n    int diamondrows;\r\n    char givencharacter;\r\n    \/\/ Give the Character as user input using scanf and\r\n    \/\/ store it in another variable.\r\n    scanf(\"%d\", &amp;diamondrows);\r\n    scanf(\"%c\", &amp;givencharacter);\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            printf(\" \");\r\n        }\r\n        \/\/ Loop from 0 to the 2 * iterator value- 1 of the\r\n        \/\/ parent For loop using another For loop(Nested For\r\n        \/\/ loop).\r\n        for (int l = 0; l &lt; ((2 * m) - 1); l++) {\r\n            \/\/ Print the given character\r\n            printf(\"%c\", givencharacter);\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        printf(\"\\n\");\r\n    }\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n    for (int m = 1; m &lt; diamondrows; m++) {\r\n        \/\/ Loop from 1 to iterator value of the parent For\r\n        \/\/ loop using another For loop(Nested For loop).\r\n        for (int n = 1; n &lt;= m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            printf(\" \");\r\n        }\r\n        \/\/ Loop from 1 to 2* (number of rows- iterator value\r\n        \/\/ of the parent for loop) using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * (diamondrows - m)); l++) {\r\n            \/\/ Print the givencharacter\r\n            printf(\"%c\", givencharacter);\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">7$\r\n          $\r\n        $$$\r\n       $$$$$\r\n     $$$$$$$\r\n   $$$$$$$$$\r\n  $$$$$$$$$$$\r\n$$$$$$$$$$$$$\r\n  $$$$$$$$$$$\r\n    $$$$$$$$$\r\n      $$$$$$$\r\n        $$$$$\r\n         $$$\r\n           $<\/pre>\n<p><strong>Related Programs<\/strong>:<\/p>\n<ul>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-half-diamond-star-pattern\/\">python program to print hollow half diamond star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-diamond-star-pattern\/\">python program to print hollow diamond star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-mirrored-half-diamond-star-pattern\/\">python program to print mirrored half diamond star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-an-inverted-star-pattern\/\">python program to print an inverted star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-rectangle-star-pattern\/\">python program to print rectangle star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-rectangle-star-pattern\/\">python program to print hollow rectangle star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-square-star-pattern\/\">python program to print square star pattern<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Are you a job seeker and trying to find simple java programs for Interview? This would be the right choice for you, just tap on the link and start preparing the java programs covered to crack the interview. Given the number of rows of the diamond pattern, the task is to print the diamond star &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/python-programs.com\/python-program-to-print-diamond-star-pattern\/\"> <span class=\"screen-reader-text\">Python Program to Print Diamond Star Pattern<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","jetpack_publicize_message":"","jetpack_is_tweetstorm":false,"jetpack_publicize_feature_enabled":true},"categories":[19,5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Python Program to Print Diamond Star Pattern - Python Programs<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/python-programs.com\/python-program-to-print-diamond-star-pattern\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Python Program to Print Diamond Star Pattern - Python Programs\" \/>\n<meta property=\"og:description\" content=\"Are you a job seeker and trying to find simple java programs for Interview? 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