{"id":12027,"date":"2021-09-30T14:30:21","date_gmt":"2021-09-30T09:00:21","guid":{"rendered":"https:\/\/python-programs.com\/?p=12027"},"modified":"2021-11-22T18:34:33","modified_gmt":"2021-11-22T13:04:33","slug":"python-program-to-print-hollow-diamond-star-pattern","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-program-to-print-hollow-diamond-star-pattern\/","title":{"rendered":"Python Program to Print Hollow Diamond Star Pattern"},"content":{"rendered":"<p>Enhancing programming skills is very important no matter what language you have chosen. So, practice frequently with these <a href=\"https:\/\/python-programs.com\/python-programming-examples-with-output\/\">simple java programs<\/a> examples and excel in coding the complex logic.<\/p>\n<p>Given the number of rows of the diamond pattern, the task is to print the Hollow diamond star pattern in C, C++, and Python<\/p>\n<p><strong>Examples:<\/strong><\/p>\n<p><strong>Example1:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>given number of rows of diamond =6<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">      *\r\n    *   *\r\n   *     *\r\n  *       *\r\n *         *\r\n*           *\r\n *         *\r\n  *       *\r\n   *     *\r\n    *   *\r\n      *<\/pre>\n<p><strong>Example2:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>given number of rows of diamond =10\r\ngiven character to print ='^'<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">          ^\r\n        ^ ^\r\n       ^   ^\r\n      ^     ^\r\n     ^       ^\r\n    ^         ^\r\n   ^           ^\r\n  ^             ^\r\n ^               ^\r\n^                 ^\r\n ^               ^\r\n  ^             ^\r\n   ^           ^\r\n    ^         ^\r\n     ^       ^\r\n      ^     ^\r\n       ^   ^\r\n        ^ ^\r\n         ^<\/pre>\n<h2>Program to Print Diamond Star Pattern in C, C++, and Python<\/h2>\n<p>Below are the ways to print Diamond Star Pattern in C, C++, and Python.<\/p>\n<ul>\n<li><a href=\"#Using_For_Loop_(Star_Character)\">Using For Loop (Star Character)<\/a><\/li>\n<li><a href=\"#Using_For_Loop_(User_Character)\">Using For Loop (User Character)<\/a><\/li>\n<\/ul>\n<h3 id=\"Using_For_Loop_(Star_Character)\">Method #1: Using For loop (Star Character)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the number of rows of the diamond pattern as static input and store it in a variable.<\/li>\n<li>Loop from 1 to the number of rows using For Loop.<\/li>\n<li>Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print star character.<\/li>\n<li>Else print space character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>loop from the number of rows -1 to 0 in decreasing order using For loop.<\/li>\n<li>Loop from 1 to number of rows- iterator value of the parent loop using another For loop(Nested For loop)<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print star character.<\/li>\n<li>Else print space character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>1) Python Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows  as static input and store it in a variable.\r\ndiamondrows = 6\r\n\r\n# Loop from 1 to the number of rows using For Loop.\r\nfor m in range(1, diamondrows+1):\r\n    # Loop from 1 to the number of rows -iterator value of the parent\r\n    # For loop using another For loop(Nested For loop).\r\n    for n in range(1, diamondrows - m + 1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 1 to the 2* iterator value of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for l in range(1, (2 * m)):\r\n        # If the value of the iterator is equal to 1 or 2* iterator value\r\n        # of the parent loop -1 then print star character.\r\n        if l == 1 or l == m * 2 - 1:\r\n            print('*', end='')\r\n        # Else print space character.\r\n        else:\r\n            print(' ', end='')\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print()\r\n\r\n# loop from number of rows -1 to 0 in decreasing order using For loop.\r\nfor m in range(diamondrows - 1, 0, -1):\r\n    # Loop from 1 to number of rows- iterator value\r\n    # of the parent loop using another For loop(Nested For loop)\r\n    for n in range(1, diamondrows - m + 1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 1 to the 2* iterator value of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for l in range(1, (2 * m)):\r\n        # If the value of the iterator is equal to 1 or 2* iterator value\r\n        # of the parent loop -1 then print star character.\r\n        if l == 1 or l == m * 2 - 1:\r\n            print('*', end='')\r\n        # Else print space character.\r\n        else:\r\n            print(' ', end='')\r\n\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print(\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">      *\r\n    *   *\r\n   *     *\r\n  *       *\r\n *         *\r\n*           *\r\n *         *\r\n  *       *\r\n   *     *\r\n    *   *\r\n      *<\/pre>\n<p><strong>2) C++ Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\nusing namespace std;\r\n\r\nint main()\r\n{\r\n\r\n    \/\/ Give the number of rows of the diamond pattern\r\n    \/\/ as static input and store it in a variable.\r\n    int diamondrows = 6;\r\n    char givencharacter = '*';\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                cout &lt;&lt; givencharacter;\r\n            \/\/ Else print space character.\r\n            else\r\n                cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n  \/\/ loop from number of rows -1 to 0 in decreasing order using For loop.\r\n\r\n    for (int m = diamondrows-1; m &gt; 0; m--) {\r\n    \/\/Loop from 1 to number of rows- iterator value\r\n    \/\/ of the parent loop using another For loop(Nested For loop)\r\n        for (int n = 1; n &lt;= diamondrows-m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                cout &lt;&lt; givencharacter;\r\n            \/\/ Else print space character.\r\n            else\r\n                cout &lt;&lt; \" \";\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">      *\r\n    *   *\r\n   *     *\r\n  *       *\r\n *         *\r\n*           *\r\n *         *\r\n  *       *\r\n   *     *\r\n    *   *\r\n      *<\/pre>\n<p><strong>3) C Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"c\">#include &lt;stdio.h&gt;\r\n\r\nint main()\r\n{\r\n    char givencharacter = '*';\r\n    \/\/ Give the number of rows of the diamond pattern\r\n    \/\/ as static input and store it in a variable.\r\n    int diamondrows = 6;\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            printf(\" \");\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                printf(\"%c\", givencharacter);\r\n            \/\/ Else print space character.\r\n            else\r\n                printf(\" \");\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        printf(\"\\n\");\r\n    }\r\n    \/\/ loop from number of rows -1 to 0 in decreasing order\r\n    \/\/ using For loop.\r\n\r\n    for (int m = diamondrows - 1; m &gt; 0; m--) {\r\n        \/\/ Loop from 1 to number of rows- iterator value\r\n        \/\/ of the parent loop using another For loop(Nested\r\n        \/\/ For loop)\r\n        for (int n = 1; n &lt;= diamondrows - m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            printf(\" \");\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                printf(\"%c\", givencharacter);\r\n            \/\/ Else print space character.\r\n            else\r\n                printf(\" \");\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">      *\r\n    *   *\r\n   *     *\r\n  *       *\r\n *         *\r\n*           *\r\n *         *\r\n  *       *\r\n   *     *\r\n    *   *\r\n      *<\/pre>\n<h3 id=\"Using_For_Loop_(User_Character)\">Method #2: Using For loop (User Character)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the number of rows of the diamond pattern as user input and store it in a variable.<\/li>\n<li>Give the character to print as user input and store it in a variable.<\/li>\n<li>Loop from 1 to the number of rows using For Loop.<\/li>\n<li>Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print given character.<\/li>\n<li>Else print space character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>loop from the number of rows -1 to 0 in decreasing order using For loop.<\/li>\n<li>Loop from 1 to number of rows- iterator value of the parent loop using another For loop(Nested For loop)<\/li>\n<li>Print the space character in the inner For loop.<\/li>\n<li>Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).<\/li>\n<li>If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print given character.<\/li>\n<li>Else print space character.<\/li>\n<li>After the end of the inner for Loops print the Newline Character.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>1) Python Implementation<\/strong><\/p>\n<ul>\n<li>Give the number of rows as user input using int(input()) and store it in a variable.<\/li>\n<li>Give the Character as user input using input() and store it in another variable.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows  as user input using int(input()) and store it in a variable.\r\ndiamondrows = int(input(\r\n    'Enter some random number of rows  = '))\r\n# Give the Character as user input using input() and store it in another variable.\r\ngivencharacter = input('Enter some random character = ')\r\n# Loop from 1 to the number of rows using For Loop.\r\nfor m in range(1, diamondrows+1):\r\n    # Loop from 1 to the number of rows -iterator value of the parent\r\n    # For loop using another For loop(Nested For loop).\r\n    for n in range(1, diamondrows - m + 1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 1 to the 2* iterator value of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for l in range(1, (2 * m)):\r\n        # If the value of the iterator is equal to 1 or 2* iterator value\r\n        # of the parent loop -1 then print givencharacter .\r\n        if l == 1 or l == m * 2 - 1:\r\n            print(givencharacter, end='')\r\n        # Else print space character.\r\n        else:\r\n            print(' ', end='')\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print()\r\n\r\n# loop from number of rows -1 to 0 in decreasing order using For loop.\r\nfor m in range(diamondrows - 1, 0, -1):\r\n    # Loop from 1 to number of rows- iterator value\r\n    # of the parent loop using another For loop(Nested For loop)\r\n    for n in range(1, diamondrows - m + 1):\r\n        # Print the space character in the inner For loop.\r\n        print(end=' ')\r\n    # Loop from 1 to the 2* iterator value of the parent For loop\r\n    # using another For loop(Nested For loop).\r\n    for l in range(1, (2 * m)):\r\n        # If the value of the iterator is equal to 1 or 2* iterator value\r\n        # of the parent loop -1 then print givencharacter .\r\n        if l == 1 or l == m * 2 - 1:\r\n            print(givencharacter, end='')\r\n        # Else print space character.\r\n        else:\r\n            print(' ', end='')\r\n\r\n    # After the end of the inner for Loops print the Newline Character.\r\n    print()\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">Enter some random number of rows = 10\r\nEnter some random character = ^ \r\n          ^\r\n        ^ ^\r\n       ^   ^\r\n      ^     ^\r\n     ^       ^\r\n    ^         ^\r\n   ^           ^\r\n  ^             ^\r\n ^               ^\r\n^                 ^\r\n ^               ^\r\n  ^             ^\r\n   ^           ^\r\n    ^         ^\r\n     ^       ^\r\n      ^     ^\r\n       ^   ^\r\n        ^ ^\r\n         ^<\/pre>\n<p><strong>2) C++ Implementation<\/strong><\/p>\n<ul>\n<li>Give the number of rows as user input using cin and store it in a variable.<\/li>\n<li>Give the Character as user input using cin and store it in another variable.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\nusing namespace std;\r\n\r\nint main()\r\n{\r\n\r\n    \/\/ Give the number of rows\r\n    \/\/ as user input using cin and store it in a\r\n    \/\/ variable.\r\n    int diamondrows;\r\n    char givencharacter;\r\n    cout &lt;&lt; \"Enter some random number of rows = \" &lt;&lt; endl;\r\n    cin &gt;&gt; diamondrows;\r\n    \/\/ Give the Character as user input using cin and store\r\n    \/\/ it in another variable.\r\n    cout &lt;&lt; \"Enter some random character = \" &lt;&lt; endl;\r\n    cin &gt;&gt; givencharacter;\r\n    cout &lt;&lt; endl;\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                cout &lt;&lt; givencharacter;\r\n            \/\/ Else print space character.\r\n            else\r\n                cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n  \/\/ loop from number of rows -1 to 0 in decreasing order using For loop.\r\n\r\n    for (int m = diamondrows-1; m &gt; 0; m--) {\r\n    \/\/Loop from 1 to number of rows- iterator value\r\n    \/\/ of the parent loop using another For loop(Nested For loop)\r\n        for (int n = 1; n &lt;= diamondrows-m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            cout &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                cout &lt;&lt; givencharacter;\r\n            \/\/ Else print space character.\r\n            else\r\n                cout &lt;&lt; \" \";\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        cout &lt;&lt; endl;\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">Enter some random number of rows = \r\n10\r\nEnter some random character = \r\n^ \r\n          ^\r\n        ^ ^\r\n       ^   ^\r\n      ^     ^\r\n     ^       ^\r\n    ^         ^\r\n   ^           ^\r\n  ^             ^\r\n ^               ^\r\n^                 ^\r\n ^               ^\r\n  ^             ^\r\n   ^           ^\r\n    ^         ^\r\n     ^       ^\r\n      ^     ^\r\n       ^   ^\r\n        ^ ^\r\n         ^<\/pre>\n<p><strong>3) C Implementation<\/strong><\/p>\n<ul>\n<li>Give the number of rows as user input using scanf and store it in a variable.<\/li>\n<li>Give the Character as user input using scanf and store it in another variable.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"c\">#include &lt;stdio.h&gt;\r\n\r\nint main()\r\n{\r\n    \/\/ Give the number of rows\r\n    \/\/  as user input using scanf and store it in a\r\n    \/\/ variable.\r\n    int diamondrows;\r\n    char givencharacter;\r\n    \/\/ Give the Character as user input using scanf and\r\n    \/\/ store it in another variable.\r\n    scanf(\"%d\", &amp;diamondrows);\r\n    scanf(\"%c\", &amp;givencharacter);\r\n    \/\/ Loop from 1 to the number of rows using For Loop.\r\n    for (int m = 1; m &lt;= diamondrows; m++) {\r\n\r\n        \/\/ Loop from 1 to the number of rows- iterator value\r\n        \/\/ of the parent For loop using another For\r\n        \/\/ loop(Nested For loop).\r\n        for (int n = 1; n &lt;= (diamondrows - m); n++) {\r\n\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n            printf(\" \");\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                printf(\"%c\", givencharacter);\r\n            \/\/ Else print space character.\r\n            else\r\n                printf(\" \");\r\n        }\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline Character.\r\n        printf(\"\\n\");\r\n    }\r\n    \/\/ loop from number of rows -1 to 0 in decreasing order\r\n    \/\/ using For loop.\r\n\r\n    for (int m = diamondrows - 1; m &gt; 0; m--) {\r\n        \/\/ Loop from 1 to number of rows- iterator value\r\n        \/\/ of the parent loop using another For loop(Nested\r\n        \/\/ For loop)\r\n        for (int n = 1; n &lt;= diamondrows - m; n++) {\r\n            \/\/ Print the space character in the inner For\r\n            \/\/ loop.\r\n           printf(\" \");\r\n        }\r\n        \/\/ Loop from 1 to the 2* iterator value of the\r\n        \/\/ parent For loop\r\n        \/\/ using another For loop(Nested For loop).\r\n        for (int l = 1; l &lt; (2 * m); l++) {\r\n            \/\/ If the value of the iterator is equal to 1 or\r\n            \/\/ 2* iterator value of the parent loop -1 then\r\n            \/\/ print givencharacter .\r\n            if (l == 1 || l == m * 2 - 1)\r\n                printf(\"%c\", givencharacter);\r\n            \/\/ Else print space character.\r\n            else\r\n                printf(\" \");\r\n        }\r\n\r\n        \/\/ After the end of the inner for Loops print the\r\n        \/\/ Newline    Character.\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">10^\r\n          ^\r\n        ^ ^\r\n       ^   ^\r\n      ^     ^\r\n     ^       ^\r\n    ^         ^\r\n   ^           ^\r\n  ^             ^\r\n ^               ^\r\n^                 ^\r\n ^               ^\r\n  ^             ^\r\n   ^           ^\r\n    ^         ^\r\n     ^       ^\r\n      ^     ^\r\n       ^   ^\r\n        ^ ^\r\n         ^<\/pre>\n<p><strong>Related Programs<\/strong>:<\/p>\n<ul>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-rectangle-star-pattern\/\">python program to print hollow rectangle star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-square-star-pattern\/\">python program to print hollow square star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-rhombus-star-pattern\/\">python program to print hollow rhombus star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-right-triangle-star-pattern\/\">python program to print hollow right triangle star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-mirrored-rhombus-star-pattern\/\">python program to print hollow mirrored rhombus star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-half-diamond-star-pattern\/\">python program to print half diamond star pattern<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-diamond-star-pattern\/\">python program to print diamond star pattern<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Enhancing programming skills is very important no matter what language you have chosen. So, practice frequently with these simple java programs examples and excel in coding the complex logic. Given the number of rows of the diamond pattern, the task is to print the Hollow diamond star pattern in C, C++, and Python Examples: Example1: &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-diamond-star-pattern\/\"> <span class=\"screen-reader-text\">Python Program to Print Hollow Diamond Star Pattern<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","jetpack_publicize_message":"","jetpack_is_tweetstorm":false,"jetpack_publicize_feature_enabled":true},"categories":[19,5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Python Program to Print Hollow Diamond Star Pattern - Python Programs<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/python-programs.com\/python-program-to-print-hollow-diamond-star-pattern\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Python Program to Print Hollow Diamond Star Pattern - Python Programs\" \/>\n<meta property=\"og:description\" content=\"Enhancing programming skills is very important no matter what language you have chosen. 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