{"id":12265,"date":"2021-09-30T15:00:34","date_gmt":"2021-09-30T09:30:34","guid":{"rendered":"https:\/\/python-programs.com\/?p=12265"},"modified":"2021-11-22T18:34:27","modified_gmt":"2021-11-22T13:04:27","slug":"python-program-to-print-a-unique-pyramid-pattern-of-digits","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-program-to-print-a-unique-pyramid-pattern-of-digits\/","title":{"rendered":"Python Program to Print a Unique Pyramid Pattern of Digits"},"content":{"rendered":"<p>If you are new to Java and want to learn the java coding skills too fast. Try practicing the core java programs with the help of the <a href=\"https:\/\/python-programs.com\/python-programming-examples-with-output\/\">Java basic programs list<\/a> available.<\/p>\n<p>Given the number of rows, the task is to Print a Unique Pyramid Pattern of Digits in C, C++, and Python<\/p>\n<p><strong>Examples:<\/strong><\/p>\n<p><strong>Example1:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>Given number of rows = 8<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n1 2 3 4 5 4 3 2 1 \r\n1 2 3 4 5 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 6 5 4 3 2 1<\/pre>\n<p><strong>Example2:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>Given number of rows = 7<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n1 2 3 4 5 4 3 2 1 \r\n1 2 3 4 5 6 5 4 3 2 1<\/pre>\n<h2>Program to Print a Unique Pyramid Pattern of Digits in C, C++, and Python<\/h2>\n<p>Below are the ways to Print a Unique Pyramid Pattern of Digits in C, C++, and Python<\/p>\n<ul>\n<li><a href=\"#Using_For_loop(Static_Input)\">Using For loop(Static Input)<\/a><\/li>\n<li><a href=\"#Using_For_loop(User_Input)\">Using For loop(User Input)<\/a><\/li>\n<\/ul>\n<h3 id=\"Using_For_loop(Static_Input)\">Method #1: Using For Loop (Static Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the number of rows as static input and store it in a variable.<\/li>\n<li>Loop from 1 to the number of rows using For loop.<\/li>\n<li>Loop from 1 to m-1 using another For loop(Nested For loop) where m is the iterator value of the parent For loop.<\/li>\n<li>Print the inner loop iterator value with space.<\/li>\n<li>Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop) where m is the iterator value of the parent For loop.<\/li>\n<li>Print the inner loop iterator value with space.<\/li>\n<li>Print the Newline character after the end of the inner loop.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>1) Python Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows as static input and store it in a variable.\r\nnumberOfRows = 8\r\n# Loop from 1 to the number of rows using For loop.\r\nfor m in range(1, numberOfRows + 1):\r\n    # Loop from 1 to m-1 using another For loop(Nested For loop)\r\n    # where m is the iterator value of the parent For loop.\r\n    for n in range(1, m - 1):\r\n      # Print the inner loop iterator value with space.\r\n        print(n, end=\" \")\r\n    # Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop)\r\n    # where m is the iterator value of the parent For loop.\r\n    for n in range(m - 1, 0, -1):\r\n      # Print the inner loop iterator value with space.\r\n        print(n, end=\" \")\r\n    # Print the Newline character after the end of the inner loop.\r\n    print()\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n1 2 3 4 5 4 3 2 1 \r\n1 2 3 4 5 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 6 5 4 3 2 1<\/pre>\n<p><strong>2) C++ Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\n#include &lt;math.h&gt;\r\nusing namespace std;\r\nint main()\r\n{\r\n\r\n    \/\/ Give the number of rows as static input and store it\r\n    \/\/ in a variable.\r\n    int numberOfRows = 8;\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n\r\n    for (int m = 1; m &lt;= numberOfRows; m++) {\r\n        \/\/ Loop from 1 to m-1 using another For loop(Nested\r\n        \/\/ For loop)\r\n        \/\/ where m is the iterator value of the parent For\r\n        \/\/ loop.\r\n        for (int n = 1; n &lt; m - 1; n++) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            cout &lt;&lt; n &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from m-1 to 0 in decreasing order using\r\n        \/\/ another For loop(Nested For loop) where m is the\r\n        \/\/ iterator value of the parent For loop.\r\n        for (int n = m - 1; n &gt; 0; n--) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            cout &lt;&lt; n &lt;&lt; \" \";\r\n        }\r\n        \/\/ Print the Newline character after the end of the\r\n        \/\/ inner loop.\r\n        cout &lt;&lt; endl;\r\n    }\r\n\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n1 2 3 4 5 4 3 2 1 \r\n1 2 3 4 5 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 6 5 4 3 2 1<\/pre>\n<p><strong>3) C Implementation<\/strong><\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"c\">#include &lt;stdio.h&gt;\r\n\r\nint main()\r\n{\r\n\r\n    \/\/ Give the number of rows as static input and store it\r\n    \/\/ in a variable.\r\n    int numberOfRows = 7;\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n\r\n    for (int m = 1; m &lt;= numberOfRows; m++) {\r\n        \/\/ Loop from 1 to m-1 using another For loop(Nested\r\n        \/\/ For loop) where m is the iterator value of the\r\n        \/\/ parent For loop.\r\n        for (int n = 1; n &lt; m - 1; n++) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            printf(\"%d \", n);\r\n        }\r\n        \/\/ Loop from m-1 to 0 in decreasing order using\r\n        \/\/ another For loop(Nested For loop) where m is the\r\n        \/\/ iterator value of the parent For loop.\r\n        for (int n = m - 1; n &gt; 0; n--) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            printf(\"%d \", n);\r\n        }\r\n        \/\/ Print the Newline character after the end of the\r\n        \/\/ inner loop.\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n1 2 3 4 5 4 3 2 1 \r\n1 2 3 4 5 6 5 4 3 2 1<\/pre>\n<h3 id=\"Using_For_loop(User_Input)\">Method #2: Using For Loop (User Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the number of rows as user input and store it in a variable.<\/li>\n<li>Loop from 1 to the number of rows using For loop.<\/li>\n<li>Loop from 1 to m-1 using another For loop(Nested For loop) where m is the iterator value of the parent For loop.<\/li>\n<li>Print the inner loop iterator value with space.<\/li>\n<li>Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop) where m is the iterator value of the parent For loop.<\/li>\n<li>Print the inner loop iterator value with space.<\/li>\n<li>Print the Newline character after the end of the inner loop.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>1) Python Implementation<\/strong><\/p>\n<p>Give the number of rows as user input using int(input()) and store it in a variable.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Give the number of rows as user input using int(input()) and store it in a variable.\r\nnumberOfRows = int(input('Enter some random number of rows = '))\r\n# Loop from 1 to the number of rows using For loop.\r\nfor m in range(1, numberOfRows + 1):\r\n    # Loop from 1 to m-1 using another For loop(Nested For loop)\r\n    # where m is the iterator value of the parent For loop.\r\n    for n in range(1, m - 1):\r\n      # Print the inner loop iterator value with space.\r\n        print(n, end=\" \")\r\n    # Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop)\r\n    # where m is the iterator value of the parent For loop.\r\n    for n in range(m - 1, 0, -1):\r\n      # Print the inner loop iterator value with space.\r\n        print(n, end=\" \")\r\n    # Print the Newline character after the end of the inner loop.\r\n    print()\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre>Enter some random number of rows = 17\r\n1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n1 2 3 4 5 4 3 2 1 \r\n1 2 3 4 5 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 10 11 10 9 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 10 11 12 11 10 9 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 10 11 12 13 12 11 10 9 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 13 12 11 10 9 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 \r\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1<\/pre>\n<p><strong>2) C++ Implementation<\/strong><\/p>\n<p>Give the number of rows as user input using cin and store it in a variable.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"cpp\">#include &lt;iostream&gt;\r\n#include &lt;math.h&gt;\r\nusing namespace std;\r\nint main()\r\n{\r\n\r\n    \/\/ Give the number of rows as user input using\r\n    \/\/ int(input()) and store it in a variable.\r\n    int numberOfRows;\r\n    cin &gt;&gt; numberOfRows;\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n\r\n    for (int m = 1; m &lt;= numberOfRows; m++) {\r\n        \/\/ Loop from 1 to m-1 using another For loop(Nested\r\n        \/\/ For loop)\r\n        \/\/ where m is the iterator value of the parent For\r\n        \/\/ loop.\r\n        for (int n = 1; n &lt; m - 1; n++) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            cout &lt;&lt; n &lt;&lt; \" \";\r\n        }\r\n        \/\/ Loop from m-1 to 0 in decreasing order using\r\n        \/\/ another For loop(Nested For loop) where m is the\r\n        \/\/ iterator value of the parent For loop.\r\n        for (int n = m - 1; n &gt; 0; n--) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            cout &lt;&lt; n &lt;&lt; \" \";\r\n        }\r\n        \/\/ Print the Newline character after the end of the\r\n        \/\/ inner loop.\r\n        cout &lt;&lt; endl;\r\n    }\r\n\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre>5\r\n1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n\r\n<\/pre>\n<p><strong>3) C Implementation<\/strong><\/p>\n<p>Give the number of rows as user input using scanf and store it in a variable.<\/p>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"c\">#include &lt;stdio.h&gt;\r\nint main()\r\n{\r\n\r\n    \/\/ Give the number of rows as user input using scanf and\r\n    \/\/ store it in a variable.\r\n    int numberOfRows;\r\n    scanf(\"%d\", &amp;numberOfRows);\r\n    \/\/ Loop from 1 to the number of rows using For loop.\r\n\r\n    for (int m = 1; m &lt;= numberOfRows; m++) {\r\n        \/\/ Loop from 1 to m-1 using another For loop(Nested\r\n        \/\/ For loop) where m is the iterator value of the\r\n        \/\/ parent For loop.\r\n        for (int n = 1; n &lt; m - 1; n++) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            printf(\"%d \", n);\r\n        }\r\n        \/\/ Loop from m-1 to 0 in decreasing order using\r\n        \/\/ another For loop(Nested For loop) where m is the\r\n        \/\/ iterator value of the parent For loop.\r\n        for (int n = m - 1; n &gt; 0; n--) {\r\n            \/\/ Print the inner loop iterator value with\r\n            \/\/ space.\r\n            printf(\"%d \", n);\r\n        }\r\n        \/\/ Print the Newline character after the end of the\r\n        \/\/ inner loop.\r\n        printf(\"\\n\");\r\n    }\r\n    return 0;\r\n}<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre>6\r\n1 \r\n1 2 1 \r\n1 2 3 2 1 \r\n1 2 3 4 3 2 1 \r\n1 2 3 4 5 4 3 2 1<\/pre>\n<p><strong>Related Programs<\/strong>:<\/p>\n<ul>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-pattern-with-a-combination-of-numbers-and-stars\/\">python program to print pattern with a combination of numbers and stars<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-first-k-digits-of-1-n-where-n-is-a-positive-integer\/\">python program to print first k digits of 1 n where n is a positive integer<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-count-the-number-of-digits-present-in-a-number\/\">python program to count the number of digits present in a number<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-binary-representation-of-a-number\/\">python program to print binary representation of a number<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-print-sum-of-negative-numbers-positive-even-numbers-and-positive-odd-numbers-in-a-list\/\">python program to print sum of negative numbers positive even numbers and positive odd numbers in a list<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-find-all-numbers-in-a-range-which-are-perfect-squares-and-sum-of-all-digits-in-the-number-is-less-than-10\/\">python program to find all numbers in a range which are perfect squares and sum of all digits in the number is less than 10<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-read-print-prime-numbers-in-a-range-using-sieve-of-eratosthenes\/\">python program to read print prime numbers in a range using sieve of eratosthenes<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>If you are new to Java and want to learn the java coding skills too fast. Try practicing the core java programs with the help of the Java basic programs list available. Given the number of rows, the task is to Print a Unique Pyramid Pattern of Digits in C, C++, and Python Examples: Example1: &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/python-programs.com\/python-program-to-print-a-unique-pyramid-pattern-of-digits\/\"> <span class=\"screen-reader-text\">Python Program to Print a Unique Pyramid Pattern of Digits<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","jetpack_publicize_message":"","jetpack_is_tweetstorm":false,"jetpack_publicize_feature_enabled":true},"categories":[19,5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Python Program to Print a Unique Pyramid Pattern of Digits - Python Programs<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/python-programs.com\/python-program-to-print-a-unique-pyramid-pattern-of-digits\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Python Program to Print a Unique Pyramid Pattern of Digits - Python Programs\" \/>\n<meta property=\"og:description\" content=\"If you are new to Java and want to learn the java coding skills too fast. 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