{"id":20654,"date":"2021-09-21T08:59:35","date_gmt":"2021-09-21T03:29:35","guid":{"rendered":"https:\/\/python-programs.com\/?p=20654"},"modified":"2021-11-22T18:36:17","modified_gmt":"2021-11-22T13:06:17","slug":"python-program-to-remove-characters-that-appear-more-than-k-times","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-program-to-remove-characters-that-appear-more-than-k-times\/","title":{"rendered":"Python Program to Remove Characters that Appear More than k Times"},"content":{"rendered":"<p>In the previous article, we have discussed <a href=\"https:\/\/python-programs.com\/python-program-to-remove-odd-occurring-characters-from-the-string\/\">Python Program to Remove Odd Occurring Characters from the String<\/a><\/p>\n<p>Given a string, K value and the task is to remove all the characters from the given string that appears more than k times.<\/p>\n<p><strong>Examples:<\/strong><\/p>\n<p><strong>Example1:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>Given String = \"goodmorningall\"\r\nGiven k value = 2<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">The given string { goodmorningall } after removal of all characters that appears more than k{ 2 } times : dmria<\/pre>\n<p><strong>Example2:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>Given String = \"hellobtechgeeks\"\r\nGiven k value= 3<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">The given string { hellobtechgeeks } after removal of all characters that appears more than k{ 3 } times : hllobtchgks<\/pre>\n<h2>Program to Remove Characters that Appear More than k Times in Python<\/h2>\n<p>Below are the ways to remove all the characters from the given string that appears more than k times in python:<\/p>\n<ul>\n<li><a href=\"#Using_Dictionary_(Hashing,_User_Input)\">Using Dictionary (Hashing, User Input)<\/a><\/li>\n<li><a href=\"#Using_Counter()_function_(Hashing,_Static_Input)\">Using Counter() function (Hashing, Static Input)<\/a><\/li>\n<li><a href=\"#Using_Counter()_function_(Hashing,_User_Input)\">Using Counter() function (Hashing, User Input)<\/a><\/li>\n<li><a href=\"#Using_Counter()_function_(Hashing,_User_Input)\">Using Counter() function (Hashing, User Input)<\/a><\/li>\n<\/ul>\n<h3 id=\"Using_Dictionary_(Hashing,_User_Input)\">Method #1: Using Dictionary (Hashing, Static Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Take a dictionary and initialize it to empty\u00a0using the {} or dict() say <strong>freqncyDictionary<\/strong>.<\/li>\n<li>Give the string as static input and store it in a variable.<\/li>\n<li>Loop in the given string using the For loop.<\/li>\n<li>Inside the For loop, Check if the string character is present in the dictionary\u00a0or not using the if conditional statement and &#8216;in&#8217; keyword.<\/li>\n<li>If it is true then increment the count of the string character in the dictionary by 1.<\/li>\n<li>Else initialize the dictionary with the string character as key and value as 1.<\/li>\n<li>Give the k value as static input and store it in a variable.<\/li>\n<li>Take a string that stores all the characters which are not occurring even a number of times and initialize it to null string using &#8220;or str()<\/li>\n<li>loop in the given string using the for loop.<\/li>\n<li>Check if the character has a frequency less than k by checking the value of that character in the frequency dictionary.<\/li>\n<li>we check using the if conditional statement<\/li>\n<li>If it is true then concatenate this character to modifd_string using string concatenation.<\/li>\n<li>Print the modifd_string string.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Take a dictionary and initialize it to empty\r\n# using the {} or dict() say freqncyDictionary.\r\nfreqncyDictionary = {}\r\n# Give the string as static input and store it in a variable\r\ngvnstrng = \"hellobtechgeeks\"\r\n# Loop in the given string using the For loop.\r\nfor i in gvnstrng:\r\n        # Inside the For loop,\r\n    # Check if the string character is present in the dictionary\r\n    # or not using the if conditional statement and 'in' keyword.\r\n    if i in freqncyDictionary.keys():\r\n                # If it is true then increment the count of the string character\r\n        # in the dictionary by 1.\r\n        freqncyDictionary[i] = freqncyDictionary[i]+1\r\n    # Else initialize the dictionary with the string character as key and value as 1.\r\n    else:\r\n        freqncyDictionary[i] = 1\r\n# Give the k value as static input and store it in a variable.\r\nk = 3\r\n# Take a string which stores all the characters which are not occuring even number\r\n# of times and initialize it to null string using \"\" or str()\r\nmodifd_string = \"\"\r\n# loop in the given string using the for loop\r\nfor charac in gvnstrng:\r\n\r\n        # check if the character has frequency less than k by checking value of that character in frequency dictionary\r\n        # we check using the if conditional statement\r\n    if(freqncyDictionary[charac] &lt; k):\r\n        # if it is true then concatenate this character to modifd_string using string concatenation\r\n        modifd_string = modifd_string+charac\r\n\r\n# print the modifd_string string\r\nprint('The given string {', gvnstrng,\r\n      '} after removal of all characters that appears more than k{', k, '} times :', modifd_string)\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">The given string { hellobtechgeeks } after removal of all characters that appears more than k{ 3 } times : hllobtchgks<\/pre>\n<h3 id=\"Using_Counter()_function_(Hashing,_Static_Input)\">Method #2: Using Dictionary (Hashing, User Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Take a dictionary and initialize it to empty\u00a0using the {} or dict() say <strong>freqncyDictionary<\/strong>.<\/li>\n<li>Give the string as the user input using the input() function and store it in a variable.<\/li>\n<li>Loop in the given string using the For loop.<\/li>\n<li>Inside the For loop, Check if the string character is present in the dictionary\u00a0or not using the if conditional statement and &#8216;in&#8217; keyword.<\/li>\n<li>If it is true then increment the count of the string character in the dictionary by 1.<\/li>\n<li>Else initialize the dictionary with the string character as key and value as 1.<\/li>\n<li>Give the k value as user input using the int(input()) function and store it in a variable.<\/li>\n<li>Take a string that stores all the characters which are not occurring even a number of times and initialize it to null string using &#8220;or str()<\/li>\n<li>loop in the given string using the for loop.<\/li>\n<li>Check if the character has a frequency less than k by checking the value of that character in the frequency dictionary.<\/li>\n<li>we check using the if conditional statement<\/li>\n<li>If it is true then concatenate this character to modifd_string using string concatenation.<\/li>\n<li>Print the modifd_string string.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Take a dictionary and initialize it to empty\r\n# using the {} or dict() say freqncyDictionary.\r\nfreqncyDictionary = {}\r\n# Give the string as the user input using the input() function and store it in a variable.\r\ngvnstrng = input(\"Enter some random string = \")\r\n# Loop in the given string using the For loop.\r\nfor i in gvnstrng:\r\n        # Inside the For loop,\r\n    # Check if the string character is present in the dictionary\r\n    # or not using the if conditional statement and 'in' keyword.\r\n    if i in freqncyDictionary.keys():\r\n                # If it is true then increment the count of the string character\r\n        # in the dictionary by 1.\r\n        freqncyDictionary[i] = freqncyDictionary[i]+1\r\n    # Else initialize the dictionary with the string character as key and value as 1.\r\n    else:\r\n        freqncyDictionary[i] = 1\r\n# Give the k value as user input using the int(input()) function and store it in a variable.\r\nk = int(input(\"Enter some random number =\"))\r\n# Take a string which stores all the characters which are not occuring even number\r\n# of times and initialize it to null string using \"\" or str()\r\nmodifd_string = \"\"\r\n# loop in the given string using the for loop\r\nfor charac in gvnstrng:\r\n\r\n        # check if the character has frequency less than k by checking value of that character in frequency dictionary\r\n        # we check using the if conditional statement\r\n    if(freqncyDictionary[charac] &lt; k):\r\n        # if it is true then concatenate this character to modifd_string using string concatenation\r\n        modifd_string = modifd_string+charac\r\n\r\n# print the modifd_string string\r\nprint('The given string {', gvnstrng,\r\n      '} after removal of all characters that appears more than k{', k, '} times :', modifd_string)\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre>Enter some random string = goodmorningall\r\nEnter some random number =2\r\nThe given string { goodmorningall } after removal of all characters that appears more than k{ 2 } times : dmria<\/pre>\n<h3 id=\"Using_Counter()_function_(Hashing,_User_Input)\">Method #3: Using Counter() function (Hashing, Static Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Import the Counter() function from collections using the import keyword.<\/li>\n<li>Give the string as static input and store it in a variable<\/li>\n<li>Calculate the frequency of all the given string characters using the Counter() function which returns the element and its frequency as key-value pair \u00a0and store this dictionary in a variable(say freqncyDictionary)<\/li>\n<li>Give the k value as static input and store it in a variable.<\/li>\n<li>Take a string that stores all the characters which are not occurring even a number of times and initialize it to null string using &#8220;or str()<\/li>\n<li>loop in the given string using the for loop.<\/li>\n<li>Check if the character has a frequency less than k by checking the value of that character in the frequency dictionary.<\/li>\n<li>we check using the if conditional statement<\/li>\n<li>If it is true then concatenate this character to modifd_string using string concatenation.<\/li>\n<li>Print the modifd_string string.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Import the Counter() function from collections using the import keyword.\r\nfrom collections import Counter\r\n# Give the string as static input and store it in a variable\r\ngvnstrng = \"hellobtechgeeks\"\r\n# Calculate the frequency of all the given string characters using the Counter()\r\n# function which returns the element and its frequency as key-value pair\r\n# and store this dictionary in a variable(say freqncyDictionary)\r\nfreqncyDictionary = Counter(gvnstrng)\r\n# Give the k value as static input and store it in a variable.\r\nk = 3\r\n# Take a string which stores all the characters which are not occuring even number\r\n# of times and initialize it to null string using \"\" or str()\r\nmodifd_string = \"\"\r\n# loop in the given string using the for loop\r\nfor charac in gvnstrng:\r\n\r\n        # check if the character has frequency less than k by checking value of that character in frequency dictionary\r\n        # we check using the if conditional statement\r\n    if(freqncyDictionary[charac] &lt; k):\r\n        # if it is true then concatenate this character to modifd_string using string concatenation\r\n        modifd_string = modifd_string+charac\r\n\r\n# print the modifd_string string\r\nprint('The given string {', gvnstrng,\r\n      '} after removal of all characters that appears more than k{', k, '} times :', modifd_string)\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">The given string { hellobtechgeeks } after removal of all characters that appears more than k{ 3 } times : hllobtchgks<\/pre>\n<h3 id=\"Using_Counter()_function_(Hashing,_User_Input)\">Method #4: Using Counter() function (Hashing, User Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Import the Counter() function from collections using the import keyword.<\/li>\n<li>Give the string as the user input using the input() function and store it in a variable.<\/li>\n<li>Calculate the frequency of all the given string characters using the Counter() function which returns the element and its frequency as key-value pair \u00a0and store this dictionary in a variable(say freqncyDictionary)<\/li>\n<li>Give the k value as user input using the int(input()) function and store it in a variable.<\/li>\n<li>Take a string that stores all the characters which are not occurring even a number of times and initialize it to null string using &#8220;or str()<\/li>\n<li>loop in the given string using the for loop.<\/li>\n<li>Check if the character has a frequency less than k by checking the value of that character in the frequency dictionary.<\/li>\n<li>we check using the if conditional statement<\/li>\n<li>If it is true then concatenate this character to modifd_string using string concatenation.<\/li>\n<li>Print the modifd_string string.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Import the Counter() function from collections using the import keyword.\r\nfrom collections import Counter\r\n# Give the string as the user input using the input() function and store it in a variable.\r\ngvnstrng = input(\"Enter some random string = \")\r\n# Calculate the frequency of all the given string characters using the Counter()\r\n# function which returns the element and its frequency as key-value pair\r\n# and store this dictionary in a variable(say freqncyDictionary)\r\nfreqncyDictionary = Counter(gvnstrng)\r\n# Give the k value as user input using the int(input()) function and store it in a variable.\r\nk = int(input(\"Enter some random number =\"))\r\n# Take a string which stores all the characters which are not occuring even number\r\n# of times and initialize it to null string using \"\" or str()\r\nmodifd_string = \"\"\r\n# loop in the given string using the for loop\r\nfor charac in gvnstrng:\r\n\r\n        # check if the character has frequency less than k by checking value of that character in frequency dictionary\r\n        # we check using the if conditional statement\r\n    if(freqncyDictionary[charac] &lt; k):\r\n        # if it is true then concatenate this character to modifd_string using string concatenation\r\n        modifd_string = modifd_string+charac\r\n\r\n# print the modifd_string string\r\nprint('The given string {', gvnstrng,\r\n      '} after removal of all characters that appears more than k{', k, '} times :', modifd_string)\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre>Enter some random string = goodmorningall\r\nEnter some random number =2\r\nThe given string { goodmorningall } after removal of all characters that appears more than k{ 2 } times : dmria<\/pre>\n<p>Dive into numerous <a href=\"https:\/\/python-programs.com\/python-programming-examples-with-output\/\">Python Programming Language Examples<\/a> for practice and get the best out of the tutorial and learn python one step at a time.<\/p>\n<ul>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-find-the-sum-of-all-highest-occurring-elements-in-an-array-list\/\">Python Program to Find the sum of all Highest Occurring Elements in an Array\/List<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-find-the-sum-of-all-even-occurring-elements-in-an-array-list\/\">Python Program to Find the Sum of all Even Occurring Elements in an Array\/List<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-remove-even-frequency-characters-from-the-string\/\">Python Program to Remove Even Frequency Characters from the String<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-delete-all-odd-frequency-elements-from-an-array-list\/\">Python Program to Delete All Odd Frequency Elements from an Array\/List<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>In the previous article, we have discussed Python Program to Remove Odd Occurring Characters from the String Given a string, K value and the task is to remove all the characters from the given string that appears more than k times. Examples: Example1: Input: Given String = &#8220;goodmorningall&#8221; Given k value = 2 Output: The &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/python-programs.com\/python-program-to-remove-characters-that-appear-more-than-k-times\/\"> <span class=\"screen-reader-text\">Python Program to Remove Characters that Appear More than k Times<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":7,"featured_media":20697,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","jetpack_publicize_message":"","jetpack_is_tweetstorm":false,"jetpack_publicize_feature_enabled":true},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Python Program to Remove Characters that Appear More than k Times - Python Programs<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/python-programs.com\/python-program-to-remove-characters-that-appear-more-than-k-times\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Python Program to Remove Characters that Appear More than k Times - Python Programs\" \/>\n<meta property=\"og:description\" content=\"In the previous article, we have discussed Python Program to Remove Odd Occurring Characters from the String Given a string, K value and the task is to remove all the characters from the given string that appears more than k times. 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