{"id":20691,"date":"2021-09-21T09:00:03","date_gmt":"2021-09-21T03:30:03","guid":{"rendered":"https:\/\/python-programs.com\/?p=20691"},"modified":"2021-11-22T18:36:16","modified_gmt":"2021-11-22T13:06:16","slug":"python-program-to-remove-elements-from-the-array-list-which-appear-strictly-less-than-k-times","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-program-to-remove-elements-from-the-array-list-which-appear-strictly-less-than-k-times\/","title":{"rendered":"Python Program to Remove Elements from the Array\/List Which Appear Strictly Less than k Times"},"content":{"rendered":"
In the previous article, we have discussed Python Program to Remove String Elements that Appear Strictly Less than k Times<\/a><\/p>\n Given a list, k value and the task is to delete all the elements from a given list that appears Strictly less than k times in python.<\/p>\n Examples:<\/strong><\/p>\n Example1:<\/strong><\/p>\n Input:<\/strong><\/p>\n Output:<\/strong><\/p>\n Example2:<\/strong><\/p>\n Input:<\/strong><\/p>\n Output:<\/strong><\/p>\n Below are the ways to delete all the elements from a given list that appears Strictly less than k times in python:<\/p>\n Approach:<\/strong><\/p>\n Below is the implementation:<\/strong><\/p>\n Output:<\/strong><\/p>\n Approach:<\/strong><\/p>\n Below is the implementation:<\/strong><\/p>\n Output:<\/strong><\/p>\n Approach:<\/strong><\/p>\n Below is the implementation:<\/strong><\/p>\n Output:<\/strong><\/p>\n Approach:<\/strong><\/p>\n Below is the implementation:<\/strong><\/p>\n Output:<\/strong><\/p>\n Find the best practical and ready-to-use Python Programming Examples<\/a> that you can simply run on a variety of platforms and never stop learning.<\/p>\n In the previous article, we have discussed Python Program to Remove String Elements that Appear Strictly Less than k Times Given a list, k value and the task is to delete all the elements from a given list that appears Strictly less than k times in python. Examples: Example1: Input: Given List = [2, 4, …<\/p>\nGiven List = [2, 4, 6, 2, 3, 5, 6]\r\nGiven k value = 1<\/pre>\n
The list [2, 4, 6, 2, 3, 5, 6] after deletion all the elements from a given list that appears strictly less than k times:\r\n[2, 6, 2, 6]<\/pre>\n
Given List = [10, 20, 30, 40, 20, 10, 20, 10, 30]\r\nGiven k value = 2<\/pre>\n
The list [10, 20, 30, 40, 20, 10, 20, 10, 30] after deletion all the elements from a given list that appears strictly less than k times:\r\n[10, 20, 20, 10, 20, 10]<\/pre>\n
Program to Remove Elements from the Array\/List Which Appear Strictly Less than k Times in Python<\/h2>\n
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Method #1: Using Dictionary (Hashing, Static Input)<\/h3>\n
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# Take a dictionary and initialize it to empty\r\n# using the {} or dict() say freqncyDictionary.\r\nfreqncyDictionary = {}\r\n# Give the list as static input and store it in a variable.\r\ngvnlst = [2, 4, 6, 2, 3, 5, 6]\r\n# Loop in the given list using the For loop.\r\nfor i in gvnlst:\r\n # Inside the For loop,\r\n # Check if the list element is present in the dictionary\r\n # or not using the if conditional statement and 'in' keyword.\r\n if i in freqncyDictionary.keys():\r\n # If it is true then increment the count of the list element\r\n # in the dictionary by 1.\r\n freqncyDictionary[i] = freqncyDictionary[i]+1\r\n # Else initialize the dictionary with the list element as key and value as 1.\r\n else:\r\n freqncyDictionary[i] = 1\r\n# Give the k value as static input and store it in a variable.\r\nk = 1\r\n# Take a new empty list say modifdlst and store it in a variable.\r\nmodifdlst = []\r\n# Loop in the given list using the For loop.\r\nfor lstelmt in gvnlst:\r\n # Check if the key in the freqncyDictionary having value greater than k\r\n # using the if conditional statement.\r\n\r\n if(freqncyDictionary[lstelmt] > k):\r\n # If it is true then append the key value to the above declared empty list modifdlst.\r\n modifdlst.append(lstelmt)\r\n# Print the list after deletion of all the elements from a given list that appears\r\n# Strictly less than k times.\r\nprint(\"The list\", gvnlst,\r\n \"after deletion all the elements from a given list that appears strictly less than k times:\")\r\nprint(modifdlst)\r\n<\/pre>\n
The list [2, 4, 6, 2, 3, 5, 6] after deletion all the elements from a given list that appears strictly less than k times:\r\n[2, 6, 2, 6]<\/pre>\n<\/div>\n
Method #2: Using Dictionary (Hashing, User Input)<\/h3>\n
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# Take a dictionary and initialize it to empty\r\n# using the {} or dict() say freqncyDictionary.\r\nfreqncyDictionary = {}\r\n# Give the list as user input using the list(),map(),split(),int functions\r\n# and store it in a variable.\r\ngvnlst = list(\r\n map(int, input('Enter some random list element separated by spaces = ').split()))\r\n# Loop in the given list using the For loop.\r\nfor i in gvnlst:\r\n # Inside the For loop,\r\n # Check if the list element is present in the dictionary\r\n # or not using the if conditional statement and 'in' keyword.\r\n if i in freqncyDictionary.keys():\r\n # If it is true then increment the count of the list element\r\n # in the dictionary by 1.\r\n freqncyDictionary[i] = freqncyDictionary[i]+1\r\n # Else initialize the dictionary with the list element as key and value as 1.\r\n else:\r\n freqncyDictionary[i] = 1\r\n# Give the k value as user input using the int(input()) function and store it in a variable.\r\nk = int(input(\"Enter some random number =\"))\r\n# Take a new empty list say modifdlst and store it in a variable.\r\nmodifdlst = []\r\n# Loop in the given list using the For loop.\r\nfor lstelmt in gvnlst:\r\n # Check if the key in the freqncyDictionary having value greater than k\r\n # using the if conditional statement.\r\n\r\n if(freqncyDictionary[lstelmt] > k):\r\n # If it is true then append the key value to the above declared empty list modifdlst.\r\n modifdlst.append(lstelmt)\r\n# Print the list after deletion of all the elements from a given list that appears\r\n# Strictly less than k times.\r\nprint(\"The list\", gvnlst,\r\n \"after deletion all the elements from a given list that appears strictly less than k times:\")\r\nprint(modifdlst)\r\n<\/pre>\n
Enter some random list element separated by spaces = 10 20 30 40 20 10 20 10 30\r\nEnter some random number =2\r\nThe list [10, 20, 30, 40, 20, 10, 20, 10, 30] after deletion all the elements from a given list that appears strictly less than k times:\r\n[10, 20, 20, 10, 20, 10]<\/pre>\n
Method #3: Using Counter() function (Hashing, Static Input)<\/h3>\n
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# Import the Counter() function from collections using the import keyword.\r\nfrom collections import Counter\r\n# Give the list as static input and store it in a variable.\r\ngvnlst = [2, 4, 6, 2, 3, 5, 6]\r\n# Calculate the frequency of all the given list elements using the Counter()\r\n# function which returns the element and its frequency as key-value pair\r\n# and store this dictionary in a variable(say freqncyDictionary)\r\nfreqncyDictionary = Counter(gvnlst)\r\n# Give the k value as static input and store it in a variable.\r\nk = 1\r\n# Take a new empty list say modifdlst and store it in a variable.\r\nmodifdlst = []\r\n# Loop in the given list using the For loop.\r\nfor lstelmt in gvnlst:\r\n # Check if the key in the freqncyDictionary having value greater than k\r\n # using the if conditional statement.\r\n\r\n if(freqncyDictionary[lstelmt] > k):\r\n # If it is true then append the key value to the above declared empty list modifdlst.\r\n modifdlst.append(lstelmt)\r\n# Print the list after deletion of all the elements from a given list that appears\r\n# Strictly less than k times.\r\nprint(\"The list\", gvnlst,\r\n \"after deletion all the elements from a given list that appears strictly less than k times:\")\r\nprint(modifdlst)\r\n<\/pre>\n
The list [2, 4, 6, 2, 3, 5, 6] after deletion all the elements from a given list that appears strictly less than k times:\r\n[2, 6, 2, 6]<\/pre>\n
Method #4: Using Counter() function (Hashing, User Input)<\/h3>\n
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# Import the Counter() function from collections using the import keyword.\r\nfrom collections import Counter\r\n# Give the list as user input using the list(),map(),split(),int functions\r\n# and store it in a variable.\r\ngvnlst = list(\r\n map(int, input('Enter some random list element separated by spaces = ').split()))\r\n# Calculate the frequency of all the given list elements using the Counter()\r\n# function which returns the element and its frequency as key-value pair\r\n# and store this dictionary in a variable(say freqncyDictionary)\r\nfreqncyDictionary = Counter(gvnlst)\r\n# Give the k value as user input using the int(input()) function and store it in a variable.\r\nk = int(input(\"Enter some random number =\"))\r\n# Take a new empty list say modifdlst and store it in a variable.\r\nmodifdlst = []\r\n# Loop in the given list using the For loop.\r\nfor lstelmt in gvnlst:\r\n # Check if the key in the freqncyDictionary having value greater than k\r\n # using the if conditional statement.\r\n\r\n if(freqncyDictionary[lstelmt] > k):\r\n # If it is true then append the key value to the above declared empty list modifdlst.\r\n modifdlst.append(lstelmt)\r\n# Print the list after deletion of all the elements from a given list that appears\r\n# Strictly less than k times.\r\nprint(\"The list\", gvnlst,\r\n \"after deletion all the elements from a given list that appears strictly less than k times:\")\r\nprint(modifdlst)<\/pre>\n
Enter some random list element separated by spaces = 10 20 30 40 20 10 20 10 30\r\nEnter some random number =2\r\nThe list [10, 20, 30, 40, 20, 10, 20, 10, 30] after deletion all the elements from a given list that appears strictly less than k times:\r\n[10, 20, 20, 10, 20, 10]<\/pre>\n
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