{"id":22749,"date":"2021-09-27T15:43:14","date_gmt":"2021-09-27T10:13:14","guid":{"rendered":"https:\/\/python-programs.com\/?p=22749"},"modified":"2021-11-22T18:35:37","modified_gmt":"2021-11-22T13:05:37","slug":"python-program-for-maximum-number-of-2x2-squares-that-can-be-fit-inside-a-right-isosceles-triangle","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-program-for-maximum-number-of-2x2-squares-that-can-be-fit-inside-a-right-isosceles-triangle\/","title":{"rendered":"Python Program for Maximum Number of 2\u00d72 Squares That Can be Fit Inside a Right Isosceles Triangle"},"content":{"rendered":"<p>In the previous article, we have discussed <a href=\"https:\/\/python-programs.com\/python-program-to-find-slope-of-a-line\/\">Python Program to Find Slope of a Line<\/a><br \/>\nGiven the base of the isosceles triangle, the task is to find the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle.<\/p>\n<p>The side of the square must be parallel to the base of the given isosceles triangle.<\/p>\n<p><strong>Examples:<\/strong><\/p>\n<p><strong>Example1:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>Given base of triangle = 8<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">The maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle =  6<\/pre>\n<p><strong>Explanation:<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-22840\" src=\"https:\/\/python-programs.com\/wp-content\/uploads\/2021\/09\/22-2-300x224.jpg\" alt=\"\" width=\"300\" height=\"224\" srcset=\"https:\/\/python-programs.com\/wp-content\/uploads\/2021\/09\/22-2-300x224.jpg 300w, https:\/\/python-programs.com\/wp-content\/uploads\/2021\/09\/22-2.jpg 506w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p><strong>Example2:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>Given base of triangle = 6<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">The maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle =  3<\/pre>\n<h2>Program for Maximum Number of 2\u00d72 Squares That Can be Fit Inside a Right Isosceles Triangle in python:<\/h2>\n<p>Below are the ways to find the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle:<\/p>\n<ul>\n<li><a href=\"#Using_Mathematical_Formula_(Static_Input)\">Using Mathematical Formula (Static Input)<\/a><\/li>\n<li><a href=\"#Using_Mathematical_Formula_(User_Input)\">Using Mathematical Formula (User Input)<\/a><\/li>\n<\/ul>\n<h3 id=\"Using_Mathematical_Formula_(Static_Input)\">Method #1: Using Mathematical Formula (Static Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the base of the triangle as static input and store it in a variable.<\/li>\n<li>Create a function to say <strong>count_Squares<\/strong><strong>()<\/strong> which takes the given base of the isosceles triangle as an argument and returns the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle.<\/li>\n<li>Inside the function, subtract 2 from the given base value as it is the extra part.<\/li>\n<li>Store it in the same variable.<\/li>\n<li>Divide the given base of the triangle by 2 since each square has a base length of 2.<\/li>\n<li>Store it in the same variable.<\/li>\n<li>Calculate the value of gvn_trianglebase * (gvn_trianglebase + 1) \/ 2 (Mathematical Formula) and store it in another variable.<\/li>\n<li>Return the above result which is the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle.<\/li>\n<li>Pass the given base of the isosceles triangle to the <strong>count_Squares() <\/strong>function and print it.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Create a function to say count_Squares() which takes the given base of the isosceles\r\n# triangle as an argument and returns the count of the maximum number of 2*2\r\n# squares required that can be fixed inside the given isosceles triangle.\r\n\r\n\r\ndef count_Squares(gvn_trianglebase):\r\n    # Inside the function, subtract 2 from the given base value as it is the extra part.\r\n    # Store it in the same variable.\r\n\r\n    gvn_trianglebase = (gvn_trianglebase - 2)\r\n    # Divide the given base of the triangle by 2 since each square has a base length of 2.\r\n    # Store it in the same variable.\r\n    gvn_trianglebase = gvn_trianglebase \/\/ 2\r\n    # Calculate the value of gvn_trianglebase * (gvn_trianglebase + 1) \/ 2\r\n    # (Mathematical Formula) and store it in another variable.\r\n    rslt = gvn_trianglebase * (gvn_trianglebase + 1) \/\/ 2\r\n    # Return the above result which is the count of the maximum number of 2*2 squares\r\n    # required that can be fixed inside the given isosceles triangle.\r\n    return rslt\r\n\r\n\r\n# Give the base of the triangle as static input and store it in a variable.\r\ngvn_trianglebase = 6\r\n# Pass the given base of the isosceles triangle to the count_Squares() function\r\n# and print it.\r\nprint(\"The maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle = \",\r\n      count_Squares(gvn_trianglebase))\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">The maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle =  3<\/pre>\n<h3 id=\"Using_Mathematical_Formula_(User_Input)\">Method #2: Using Mathematical Formula (User Input)<\/h3>\n<p><strong>Approach:<\/strong><\/p>\n<ul>\n<li>Give the base of the triangle as user input using the int(input()) function and store it in a variable.<\/li>\n<li>Create a function to say <strong>count_Squares<\/strong><strong>()<\/strong> which takes the given base of the isosceles triangle as an argument and returns the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle.<\/li>\n<li>Inside the function, subtract 2 from the given base value as it is the extra part.<\/li>\n<li>Store it in the same variable.<\/li>\n<li>Divide the given base of the triangle by 2 since each square has a base length of 2.<\/li>\n<li>Store it in the same variable.<\/li>\n<li>Calculate the value of gvn_trianglebase * (gvn_trianglebase + 1) \/ 2 (Mathematical Formula) and store it in another variable.<\/li>\n<li>Return the above result which is the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle.<\/li>\n<li>Pass the given base of the isosceles triangle to the <strong>count_Squares() <\/strong>function and print it.<\/li>\n<li>The Exit of the Program.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># Create a function to say count_Squares() which takes the given base of the isosceles\r\n# triangle as an argument and returns the count of the maximum number of 2*2\r\n# squares required that can be fixed inside the given isosceles triangle.\r\n\r\n\r\ndef count_Squares(gvn_trianglebase):\r\n    # Inside the function, subtract 2 from the given base value as it is the extra part.\r\n    # Store it in the same variable.\r\n\r\n    gvn_trianglebase = (gvn_trianglebase - 2)\r\n    # Divide the given base of the triangle by 2 since each square has a base length of 2.\r\n    # Store it in the same variable.\r\n    gvn_trianglebase = gvn_trianglebase \/\/ 2\r\n    # Calculate the value of gvn_trianglebase * (gvn_trianglebase + 1) \/ 2\r\n    # (Mathematical Formula) and store it in another variable.\r\n    rslt = gvn_trianglebase * (gvn_trianglebase + 1) \/\/ 2\r\n    # Return the above result which is the count of the maximum number of 2*2 squares\r\n    # required that can be fixed inside the given isosceles triangle.\r\n    return rslt\r\n\r\n\r\n# Give the base of the triangle as user input using the int(input()) function\r\n# and store it in a variable.\r\ngvn_trianglebase = int(input(\"Enter some random number = \"))\r\n# Pass the given base of the isosceles triangle to the count_Squares() function\r\n# and print it.\r\nprint(\"The maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle = \",\r\n      count_Squares(gvn_trianglebase))\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre>Enter some random number = 8\r\nThe maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle = 6<\/pre>\n<p>Find a comprehensive collection of <a href=\"https:\/\/python-programs.com\/python-programming-examples-with-output\/\">Examples of Python Programs<\/a> ranging from simple ones to complex ones to guide you throughout your coding journey.<\/p>\n<ul>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-find-line-passing-through-2-points\/\">Python Program to Find Line Passing Through 2 Points<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-find-the-mid-point-of-a-line\/\">Python Program to Find the Mid-Point of a Line<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-for-section-formula-point-that-divides-a-line-in-given-ratio\/\">Python Program for Section Formula (Point that Divides a Line in Given Ratio)<\/a><\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-find-slope-of-a-line\/\">Python Program to Find Slope of a Line<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>In the previous article, we have discussed Python Program to Find Slope of a Line Given the base of the isosceles triangle, the task is to find the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle. The side of the square must be parallel to &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/python-programs.com\/python-program-for-maximum-number-of-2x2-squares-that-can-be-fit-inside-a-right-isosceles-triangle\/\"> <span class=\"screen-reader-text\">Python Program for Maximum Number of 2\u00d72 Squares That Can be Fit Inside a Right Isosceles Triangle<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":7,"featured_media":22832,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","jetpack_publicize_message":"","jetpack_is_tweetstorm":false,"jetpack_publicize_feature_enabled":true},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Python Program for Maximum Number of 2\u00d72 Squares That Can be Fit Inside a Right Isosceles Triangle - Python Programs<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/python-programs.com\/python-program-for-maximum-number-of-2x2-squares-that-can-be-fit-inside-a-right-isosceles-triangle\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Python Program for Maximum Number of 2\u00d72 Squares That Can be Fit Inside a Right Isosceles Triangle - Python Programs\" \/>\n<meta property=\"og:description\" content=\"In the previous article, we have discussed Python Program to Find Slope of a Line Given the base of the isosceles triangle, the task is to find the count of the maximum number of 2*2 squares required that can be fixed inside the given isosceles triangle. 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