{"id":25395,"date":"2021-11-10T09:38:56","date_gmt":"2021-11-10T04:08:56","guid":{"rendered":"https:\/\/python-programs.com\/?p=25395"},"modified":"2021-11-10T09:38:56","modified_gmt":"2021-11-10T04:08:56","slug":"python-cmath-acosh-method-with-examples","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-cmath-acosh-method-with-examples\/","title":{"rendered":"Python cmath.acosh() Method with Examples"},"content":{"rendered":"

cmath.acosh() Method in Python:<\/strong><\/p>\n

The cmath.acosh() method returns the complex number’s inverse hyperbolic cosine.<\/p>\n

There is one branch cut:<\/p>\n

Extending left along the real axis from 1 to -\u221e , continuous from above<\/p>\n

Syntax:<\/strong><\/p>\n

cmath.acosh(x)<\/pre>\n

Parameters<\/strong><\/p>\n

x:<\/strong> This is Required. The number used to calculate the inverse hyperbolic cosine of<\/p>\n

Return Value:<\/strong><\/p>\n

Returns a complex value that represents a number’s inverse hyperbolic arc cosine.<\/p>\n

Examples:<\/strong><\/p>\n

Example1:<\/strong><\/p>\n

Input:<\/strong><\/p>\n

Given Complex Number = 3+4j<\/pre>\n

Output:<\/strong><\/p>\n

The given complex number's (3+4j) inverse hyperbolic cosine value  = \r\n(2.305509031243477+0.9368124611557198j)<\/pre>\n

Example2:<\/strong><\/p>\n

Input:<\/strong><\/p>\n

Given realpart = 5\r\nGiven imaginary part = 2<\/pre>\n

Output:<\/strong><\/p>\n

The given complex number's (5+2j) inverse hyperbolic cosine value = \r\n(2.37054853731792+0.38656464251987466j)<\/pre>\n

Note:<\/strong> The above input format is for dynamic input.<\/p>\n

cmath.acosh() Method with Examples in Python<\/h2>\n