{"id":25665,"date":"2021-12-04T09:19:05","date_gmt":"2021-12-04T03:49:05","guid":{"rendered":"https:\/\/python-programs.com\/?p=25665"},"modified":"2021-12-04T09:19:05","modified_gmt":"2021-12-04T03:49:05","slug":"python-solution-to-the-ladders-problem","status":"publish","type":"post","link":"https:\/\/python-programs.com\/python-solution-to-the-ladders-problem\/","title":{"rendered":"Python Solution to the Ladders Problem"},"content":{"rendered":"

In this session, we will learn about The Ladders Problem, which is a highly interesting problem. Let us first define what we hope to accomplish with this problem.<\/p>\n

Let us First See, What the Ladders Problem is?<\/h4>\n

In the problem, we are given two inputs: the number of steps and the maximum number of steps that a man can take at one time.<\/p>\n

For example, if the maximum number of steps is 3, At any given time, a person can take one, two, or three steps.<\/p>\n

We must count all of the ways the man can reach the top of the ladder by taking one, two, or three steps at a time.<\/p>\n

Here Comes the Solution<\/h4>\n

The problem may now be solved with standard looping and if-else statements. However, following the Recursion technique is a preferable option. If you are unfamiliar with how Recursion works, I recommend just having a glance over it.<\/p>\n

To answer this problem, we shall seek the smallest problems, i.e. for n = 1 to n = n.<\/p>\n

Consider that the maximum number of steps is three.<\/p>\n

No of steps in a ladder (n)\u00a0<\/strong> \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0 Total possible Ways\u00a0 \u00a0<\/strong><\/p>\n

1\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Only one possible way<\/p>\n

2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a02\u00a0 Possible ways – Take 1 step two times or 2 steps 1 time<\/p>\n

3\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 4\u00a0 possible ways – Take 1 step 3 times, Take 2 steps 1 time and 1 step 1\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 time, Take 1 step 1 time and 2 steps 1 time, Take 3 steps 1 time Take\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a01\u00a0 step<\/p>\n

n>3\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(Take 1 step+ Take 2 steps + Take 3 steps ) and find the remaining<\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0F(n) = F(n-1)+F(n-2)+F(n-3)<\/strong><\/p>\n

Python code<\/h4>\n

In this case, we are calculating the number of methods for k maximum steps. As a result, we shall compute the values in the order (n-1), (n-2), (n-3) and so on till (n-k).<\/p>\n

Finally, we will add together all of the values obtained and return the final result. The code for implementing the same is provided below.<\/p>\n

Method #1: Using Built-in Functions (Static Input)<\/h3>\n

Approach:<\/strong><\/p>\n