{"id":6717,"date":"2021-05-22T10:14:25","date_gmt":"2021-05-22T04:44:25","guid":{"rendered":"https:\/\/python-programs.com\/?p=6717"},"modified":"2021-11-22T18:40:46","modified_gmt":"2021-11-22T13:10:46","slug":"disarium-number-in-python","status":"publish","type":"post","link":"https:\/\/python-programs.com\/disarium-number-in-python\/","title":{"rendered":"Disarium Number in Python"},"content":{"rendered":"<p><strong>Disarium Number:<\/strong><\/p>\n<p>A Disarium number is one in which the sum of each digit raised to the power of its respective position equals the original number.<\/p>\n<p>like 135 , 89 etc.<\/p>\n<p><strong>Example1:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>number =135<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">135 is disarium number<\/pre>\n<p><strong>Explanation:<\/strong><\/p>\n<pre>Here 1^1 + 3^2 + 5^3 = 135 so it is disarium Number<\/pre>\n<p><strong>Example2:<\/strong><\/p>\n<p><strong>Input:<\/strong><\/p>\n<pre>number =79<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">79 is not disarium number<\/pre>\n<p><strong>Explanation:<\/strong><\/p>\n<pre>Here 7^1 + 9^2 = 87 not equal to 79  so it is not disarium Number<\/pre>\n<h2>Disarium Number in Python<\/h2>\n<p>Below are the ways to check Disarium number in python<\/p>\n<ul>\n<li><a href=\"#Using_while_loop\">Using while loop<\/a><\/li>\n<li><a href=\"#By_converting_the_number_to_string_and_Traversing_the_string_to_extract_the_digits\">By converting the number to string and Traversing the string to extract the digits<\/a><\/li>\n<\/ul>\n<p>Explore more instances related to python concepts from <a href=\"https:\/\/python-programs.com\/python-programming-examples-with-output\/\">Python Programming Examples<\/a> Guide and get promoted from beginner to professional programmer level in Python Programming Language.<\/p>\n<h3 id=\"Using_while_loop\">Method #1: Using while loop<\/h3>\n<p><strong>Algorithm:<\/strong><\/p>\n<ul>\n<li>Scan the number and calculate the size of the number.<\/li>\n<li>Make a copy of the number so you can verify the outcome later.<\/li>\n<li>Make a result variable (with a value of 0) and an iterator ( set to the size of the number)<\/li>\n<li>Create a while loop to go digit by digit through the number.<\/li>\n<li>On each iteration, multiply the result by a digit raised to the power of the iterator value.<\/li>\n<li>On each traversal, increment the iterator.<\/li>\n<li>Compare the result value to a copy of the original number.<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># given number\r\nnum = 135\r\n# intialize result to zero(ans)\r\nans = 0\r\n# calculating the digits\r\ndigits = len(str(num))\r\n# copy the number in another variable(duplicate)\r\ndup_number = num\r\nwhile (dup_number != 0):\r\n\r\n    # getting the last digit\r\n    remainder = dup_number % 10\r\n\r\n    # multiply the result by a digit raised to the power of the iterator value.\r\n    ans = ans + remainder**digits\r\n    digits = digits - 1\r\n    dup_number = dup_number\/\/10\r\n# It is disarium number if it is equal to original number\r\nif(num == ans):\r\n    print(num, \"is disarium number\")\r\nelse:\r\n    print(num, \"is not disarium number\")\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">135 is disarium number<\/pre>\n<h3 id=\"By_converting_the_number_to_string_and_Traversing_the_string_to_extract_the_digits\">Method #2: By converting the number to string and Traversing the string to extract the digits<\/h3>\n<p><strong>Algorithm:<\/strong><\/p>\n<ul>\n<li>Initialize a variable say <strong>ans<\/strong> to 0<\/li>\n<li>Using a new variable, we must convert the given number to a string.<\/li>\n<li>Take a temp count =1 and increase the count after each iteration.<\/li>\n<li>Iterate through the string, convert each character to an integer, multiply the <strong>ans<\/strong> by a digit raised to the power of the count.<\/li>\n<li>If the <strong>ans<\/strong> is equal to given number then it is disarium number<\/li>\n<\/ul>\n<p><strong>Below is the implementation:<\/strong><\/p>\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\"># given number\r\nnum = 135\r\n# intialize result to zero(ans)\r\nans = 0\r\n# make a temp count to 1\r\ncount = 1\r\n# converting given number to string\r\nnumString = str(num)\r\n# Traverse through the string\r\nfor char in numString:\r\n    # Converting the character of string to integer\r\n    # multiply the ans by a digit raised to the power of the iterator value.\r\n    ans = ans+int(char)**count\r\n    count = count+1\r\n# It is disarium number if it is equal to original number\r\nif(num == ans):\r\n    print(num, \"is disarium number\")\r\nelse:\r\n    print(num, \"is not disarium number\")\r\n<\/pre>\n<p><strong>Output:<\/strong><\/p>\n<pre id=\"codeOutputPre\">135 is disarium number<\/pre>\n<p><strong>Related Programs<\/strong>:<\/p>\n<ul>\n<li><a href=\"https:\/\/python-programs.com\/python-get-number-of-elements-in-a-list-list-of-lists-or-nested-list\/\">python get number of elements in a list list of lists or nested list<\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-count-number-of-true-elements-in-numpy-array-in-python\/\">python count number of true elements in numpy array in python<\/li>\n<li><a href=\"https:\/\/python-programs.com\/harshad-number-in-python\/\">harshad number in python<\/li>\n<li><a href=\"https:\/\/python-programs.com\/write-a-program-to-reverse-a-number-in-python\/\">write a program to reverse a number in python<\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-count-the-number-of-digits-present-in-a-number\/\">python program to count the number of digits present in a number<\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-find-the-missing-number-in-an-array-list\/\">python program to find the missing number in an array list<\/li>\n<li><a href=\"https:\/\/python-programs.com\/python-program-to-count-set-bits-in-a-number\/\">python program to count set bits in a number<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Disarium Number: A Disarium number is one in which the sum of each digit raised to the power of its respective position equals the original number. like 135 , 89 etc. Example1: Input: number =135 Output: 135 is disarium number Explanation: Here 1^1 + 3^2 + 5^3 = 135 so it is disarium Number Example2: &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/python-programs.com\/disarium-number-in-python\/\"> <span class=\"screen-reader-text\">Disarium Number in Python<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":7,"featured_media":6728,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","jetpack_publicize_message":"","jetpack_is_tweetstorm":false,"jetpack_publicize_feature_enabled":true},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.9 - 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