Dictionaries are the implementation by Python of a data structure associative array. A dictionary is a collection of pairs of key values. A key pair and its associated value represent each key pair.

The list of key value pairs in curly braces that is separated by comma defines a dictionary. Column ‘:’ separates the value of each key.

A dictionary cannot be sorted only to get a representation of the sorted dictionary. Inherently, dictionaries are orderless, but not other types, including lists and tuples. Therefore, you need an ordered data type, which is a listâ€”probably a list of tuples.

In this post, we will look at how to sort a dictionary by key or value

**Examples:**

### By keys

**Input:**

dictionary = {'this': 200, 'is':100, 'BTechGeeks':300}

**Output:**

BTechGeeks : 300 is : 100 this :200

**Input:**

dictionary = {'this': 100, 'is':200, 'BTechGeeks':300}

**Output:**

is : 100 this : 200 BTechGeeks : 300

## Sort a Dictionary by Key/Value

There are several ways to sort a dictionary by key or value some of them are:

- Using items() function
- Using dict.keys() method
- Sorting the dictionary keys in reverse order
- Using sorted() and items() functions to sort dictionary by value
- Using sorted() + items() +reverse() functions to sort dictionary by value in reverse order

### Sort Dictionary by keys:

### Method #1: Using items() function

A view object is returned by the items() method. The object view contains the dictionary’s key-value pairs as tuples in a list.

The object displays any modifications made in the dictionary.

**Below is the implementation:**

# Given dictionary dictionary = {'this': 200, 'is': 100, 'BTechGeeks': 300} # convert the dictionary to list using items() dictitems = dictionary.items() # Using sorted() traverse this list for i in sorted(dictitems): # print key and value print(i[0], ":", i[1])

**Output:**

BTechGeeks : 300 is : 100 this :200

### Method #2:Using dict.keys() method

- Convert the keys of the dictionary to list .
- Sort the list .
- Print the corresponding keys and values as you traverse the list.

**Below is the implementation:**

# Given dictionary dictionary = {'this': 200, 'is': 100, 'BTechGeeks': 300} # convert the dictionary to list using dict.keys dictlist = list(dictionary.keys()) # sort the list dictlist.sort() # Print the corresponding key and value by traversing this list for key in dictlist: # print key and value print(key, ":", dictionary[key])

**Output:**

BTechGeeks : 300 is : 100 this :200

### Method #3: Sorting the dictionary keys in reverse order

Both of the previous solutions sorted the dictionary ascending orderÂ by key. What if we were to sort the contents by the keys in decreasing order? This can be accomplished by simply passing an attribute to the sorted() function, such as reverse=True.

**Below is the implementation:**

# Given dictionary dictionary = {'this': 200, 'is': 100, 'BTechGeeks': 300} # convert the dictionary to list using items() dictitems = dictionary.items() # Using sorted() traverse this list in descending order for i in sorted(dictitems, reverse=True): # print key and value print(i[0], ":", i[1])

**Output:**

this : 200 is : 100 BTechGeeks : 300

### Sort Dictionary by Values:

### Using sorted() and items() functions to sort dictionary by value

We’ll use the same sorted() function and transfer a key function that returns the first index element of the tuple, i.e. the value field from the key/value pair, to sort dictionary elements by value.

**Below is the implementation:**

# Given dictionary dictionary = {'this': 200, 'is': 100, 'BTechGeeks': 300} # convert the dictionary to list using items() dictitems = dictionary.items() # Using sorted() traverse this list in # using key to sort by values for i in sorted(dictitems, key=lambda x: x[1]): # print key and value print(i[0], ":", i[1])

**Output:**

is : 100 this : 200 BTechGeeks : 300

### Using sorted() + items() +reverse() functions to sort dictionary by value in reverse order

This can be accomplished by simply passing an attribute to the sorted() function, such as reverse=True.

**Below is the implementation:**

# Given dictionary dictionary = {'this': 200, 'is': 100, 'BTechGeeks': 300} # convert the dictionary to list using items() dictitems = dictionary.items() # Using sorted() traverse this list in # using key to sort by values for i in sorted(dictitems, key=lambda x: x[1], reverse=True): # print key and value print(i[0], ":", i[1])

**Output:**

BTechGeeks : 300 this : 200 is : 100

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