Python Program for Neon Number

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Given a number, the task is to check whether the given number is a Neon Number or not in Python.

Neon Number:

A Neon Number is a number whose square sum of digits equals the original number.

Ex: 9

Square of 9 =81

Sum of digits of square = 8 +1 =9 ,So it is Neon Number

Examples:

Example1:

Input:

Given Number = 9

Output:

The Given Number [ 9 ] is a neon Number

Example2:

Input:

Given Number =123

Output:

The Given Number [ 123 ] is not a neon Number

Program for Neon Number in Python

Below are the ways to check whether the given number is a Neon Number or Not.

Using list() and sum() functions (Static Input)
Using list() and sum() functions (User Input)

Method #1: Using list() and sum() functions (Static Input)

Approach:

Give the number as static input and store it in a variable.
Calculate the square of the given number using the ** operator or multiply the given number by itself and store it in a variable.
Convert this squared number into a list of digits using list(),int(),map(),str() functions.
Store this list in a variable.
Calculate the sum of digits of this list using the sum() function.
Check if this sum is equal to the given number or not using the If conditional statement.
If it is true then the given number is a Neon Number.
Else the given number is not a Neon Number.
The Exit of the Program.

Below is the implementation:

#Give the number as static input and store it in a variable.
givnumb=9
#Calculate the square of the given number using the ** operator 
#or multiply the given number by itself and store it in a variable.
squarnumb=givnumb**2
#Convert this squared number into a list of digits
#using list(),int(),map(),str() functions.
#Store this list in a variable.
numbedigit=list(map(int,str(givnumb)))
#Calculate the sum of digits of this list using the sum() function.
sumdigi=sum(numbedigit)
#Check if this sum is equal to the given number 
#or not using the If conditional statement.
#If it is true then the given number is a Neon Number.
if(sumdigi==givnumb):
  print('The Given Number [',givnumb,'] is a neon Number')
#Else the given number is not a Neon Number.
else:
    print('The Given Number [',givnumb,'] is not a neon Number')

Output:

The Given Number [ 9 ] is a neon Number

Method #2: Using list() and sum() functions (User Input)

Approach:

Give the number as user input using the int(input()) function and store it in a variable.
Calculate the square of the given number using the ** operator or multiply the given number by itself and store it in a variable.
Convert this squared number into a list of digits using list(),int(),map(),str() functions.
Store this list in a variable.
Calculate the sum of digits of this list using the sum() function.
Check if this sum is equal to the given number or not using the If conditional statement.
If it is true then the given number is a Neon Number.
Else the given number is not a Neon Number.
The Exit of the Program.

Below is the implementation:

# Give the number as user input using int(input()) function and store it in a variable
givnumb = int(input('Enter some random number ='))
# Calculate the square of the given number using the ** operator
# or multiply the given number by itself and store it in a variable.
squarnumb = givnumb**2
# Convert this squared number into a list of digits
# using list(),int(),map(),str() functions.
# Store this list in a variable.
numbedigit = list(map(int, str(givnumb)))
# Calculate the sum of digits of this list using the sum() function.
sumdigi = sum(numbedigit)
# Check if this sum is equal to the given number
# or not using the If conditional statement.
# If it is true then the given number is a Neon Number.
if(sumdigi == givnumb):
    print('The Given Number [', givnumb, '] is a neon Number')
# Else the given number is not a Neon Number.
else:
    print('The Given Number [', givnumb, '] is not a neon Number')

Output:

Enter some random number =123
The Given Number [ 123 ] is not a neon Number

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