# Python Program to Accept Three Digits and Print all Possible Combinations from the Digits

We will learn how to print all combinations of three different numbers in this python programming lesson. The application will accept three digits from the user / we give input as static and print out every possible combination of the three digits.

Examples:

Example1:

Input:

given three numbers = 1 9 2

Output:

1 9 2
1 2 9
9 1 2
9 2 1
2 1 9
2 9 1

Example2:

Input:

given three numbers = 3 7 5

Output:

Enter first digit = 3
Enter second digit = 7
Enter third digit = 5
3 7 5
3 5 7
7 3 5
7 5 3
5 3 7
5 7 3

Example3:

Input:

given three numbers = 44 389 72

Output:

44 389 72
44 72 389
389 44 72
389 72 44
72 44 389
72 389 44

## Python Program to Print all Possible Combinations of the three Digits

There are several methods to print all the possible combinations of the three numbers some of them are:

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### General Approach

• To print out the combination of all digits, we shall utilize three loops.
• Take the user’s numbers as input. These values should be saved in three distinct variables.
• Put all of these numbers in a list.
• Print out the combination of these numbers using three for loops.
• While printing the numerals, all three loops represent the three-position. As a result, if the current index of these loops is not the same, we shall print any value.

### Method #1: Using Nested loops (Static input)

Approach:

• We give the three digits input as static
• For ease of comparison, all of the items are appended to a list.
• The for loops have a value between 0 and 2, which corresponds to the indexes of the three elements in the list.
• If none of the indexes match, the element associated with the specific element in the list is printed.

Below is the implementation:

# given three digits here we took the input as static
firstDigit = 1
secondDigit = 9
thirdDigit = 2
# Taking a empty list to store the given three digits
digitsList = []
# appending all the three digits to the digitsList
digitsList.append(firstDigit)
digitsList.append(secondDigit)
digitsList.append(thirdDigit)
# Using nested loops
for i in range(3):
for j in range(3):
for k in range(3):
if(i != j & j != k & k != i):
print(digitsList[i], digitsList[j], digitsList[k])


Output:

1 9 2
1 2 9
9 1 2
9 2 1
2 1 9
2 9 1

Note:

This method also works for three numbers as shown below

Below is the implementation:

# given three digits here we took the input as static
firstDigit = 44
secondDigit = 53
thirdDigit = 456
# Taking a eempty list to store the given three digits
digitsList = []
# appending all the three digits to the digitsList
digitsList.append(firstDigit)
digitsList.append(secondDigit)
digitsList.append(thirdDigit)
# Using nested loops
for i in range(3):
for j in range(3):
for k in range(3):
if(i != j & j != k & k != i):
print(digitsList[i], digitsList[j], digitsList[k])


Output:

44 53 456
44 456 53
53 44 456
53 456 44
456 44 53
456 53 44

### Method #2: Using Nested loops (User input)

Approach:

• The first, second, and third digits must be entered by the user.
• For ease of comparison, all of the items are appended to a list.
• The for loops have a value between 0 and 2, which corresponds to the indexes of the three elements in the list.
• If none of the indexes match, the element associated with the specific element in the list is printed.

Below is the implementation:

# given three digits here we took the input as static
firstDigit = int(input("Enter first digit = "))
secondDigit = int(input("Enter second digit = "))
thirdDigit = int(input("Enter third digit = "))
# Taking a eempty list to store the given three digits
digitsList = []
# appending all the three digits to the digitsList
digitsList.append(firstDigit)
digitsList.append(secondDigit)
digitsList.append(thirdDigit)
# Using nested loops
for i in range(3):
for j in range(3):
for k in range(3):
if(i != j & j != k & k != i):
print(digitsList[i], digitsList[j], digitsList[k])


Output:

Enter first digit = 3
Enter second digit = 7
Enter third digit = 5
3 7 5
3 5 7
7 3 5
7 5 3
5 3 7
5 7 3

### Method #3:Using permutations() function

Python has built-in techniques for finding permutations and combinations of a sequence. These techniques are included in the itertools package.

To implement the permutations function in Python, first import the itertools package. This method accepts a list as input and returns an object list of tuples containing all permutations in list form.

We will pass the digitsList as argument to permutations function

Below is the implementation:

# importing permutations from itertools
from itertools import permutations
# given three digits here we took the input as static
firstDigit = 4
secondDigit = 3
thirdDigit = 7
# Taking a eempty list to store the given three digits
digitsList = []
# appending all the three digits to the digitsList
digitsList.append(firstDigit)
digitsList.append(secondDigit)
digitsList.append(thirdDigit)
# Using permutations function

totalcombs = permutations(digitsList, 3)
# printing all combinations
for i in totalcombs:
print(*i)


Output:

4 3 7
4 7 3
3 4 7
3 7 4
7 4 3
7 3 4

Note:

This method also works for three numbers as shown below

Below is the implementation:

# importing permutations from itertools
from itertools import permutations
# given three digits here we took the input as static
firstDigit = 44
secondDigit = 389
thirdDigit = 72
# Taking a eempty list to store the given three digits
digitsList = []
# appending all the three digits to the digitsList
digitsList.append(firstDigit)
digitsList.append(secondDigit)
digitsList.append(thirdDigit)
# Using permutations function

totalcombs = permutations(digitsList, 3)
# printing all combinations
for i in totalcombs:
print(*i)


Output:

44 389 72
44 72 389
389 44 72
389 72 44
72 44 389
72 389 44

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