Python Program to Check Whether Sum of digits at Odd places of a Number is Divisible by K

In the previous article, we have discussed Python Program to Find Even Digits Sum and Odd Digits Sum Divisible by 4 and 3 Respectively
The task is to check if the sum of digits at odd places of a given number is divisible by the another given input number say K.

Examples:

Example1:

Input:

Given  Number = 24689131
Given  another Number (k) = 2

Output:

The sum of digits at odd places of the given number{ 24689131 } is divisible by the another given number k{ 2 }

Example2:

Input:

Given Number = 12573
Given another Number (k) = 5

Output:

The sum of digits at odd places of the given number{ 12573 } is not divisible by the another given number k{ 5 }

Program to Check Whether Sum of digits at Odd places of a Number is Divisible by K in Python

Below are the ways to check if the sum of digits at odd places of a given number is divisible by the another given input number say K.

Using For Loop (Static Input)
Using For loop (User Input)

Method #1: Using For Loop (Static Input)

Approach:

Give the number as static input and store it in a variable.
Give the other number k as static input and store it in another variable.
Convert the given number to a string using the str() function and store it in another variable.
Create a list of digits say “digtslst” using map(),list(),int functions.
Store it in another variable.
Take another variable say “od_sum” and initialize it with 0.
Loop in the above list of digits until the length of the “digtslst” using the for loop.
Check if the iterator value is odd or not using the if conditional statement.
If the statement is true, then add the element of digits list at the iterator value to the “od_sum” and store it in the same variable od_sum.
Check if the od_sum modulus given number k is equal to 0 or not using the if conditional statement.
If the statement is true, then print “The sum of digits at odd places of the given number is divisible by the another given number k.
If the statement is false, then print “The sum of digits at odd places of the given number is Not divisible by the another given number k.
The Exit of the Program.

Below is the implementation:

# Give the number as static input and store it in a variable.
gvn_numb = 12573
# Give the other number k as static input and store it in another variable.
gvn_k = 5
# Convert the given number to a string using the str() function and store it in
# another variable.
stringnum = str(gvn_numb)
# Create a list of digits say "digtslst" using map(),list(),int functions.
digtslst = list(map(int, stringnum))
# Take a variable say "od_sum" and initialize it with 0.
od_sum = 0
# Loop in the above list of digits until the length of the "digtslst" using the for loop.
for itr in range(len(digtslst)):
    # Check if the iterator value is odd or not using
    # the if conditional statement.
    if(itr % 2 != 0):
        # If the statement is true, then add the element of digits list at iterator value to
        # the "od_sum"  and store it in the same variable od_sum.
        od_sum += digtslst[itr]
# Check if the od_sum modulus given number k is equal to 0 or not using the if conditional
# statement.
if(od_sum % gvn_k == 0):
    # If the statement is true, then print "The sum of digits at odd places of the given
    # number is divisible by the another given number k.
    print("The sum of digits at odd places of the given number{", gvn_numb,
          "} is divisible by the another given number k{", gvn_k, "}")
else:
    # If the statement is false, then print "The sum of digits at odd places of the given
    # number is Not divisible by the another given number k.
    print("The sum of digits at odd places of the given number{", gvn_numb,
          "} is not divisible by the another given number k{", gvn_k, "}")

Output:

The sum of digits at odd places of the given number{ 12573 } is not divisible by the another given number k{ 5 }

Method #2: Using For loop (User Input)

Approach:

Give the number as user input using the int(input()) function and store it in a variable.
Give the other number k as user input using the int(input()) function and store it in another variable.
Convert the given number to a string using the str() function and store it in another variable.
Create a list of digits say “digtslst” using map(),list(),int functions.
Store it in another variable.
Take another variable say “od_sum” and initialize it with 0.
Loop in the above list of digits until the length of the “digtslst” using the for loop.
Check if the iterator value is odd or not using the if conditional statement.
If the statement is true, then add the element of digits list at the iterator value to the “od_sum” and store it in the same variable od_sum.
Check if the od_sum modulus given number k is equal to 0 or not using the if conditional statement.
If the statement is true, then print “The sum of digits at odd places of the given number is divisible by the another given number k.
If the statement is false, then print “The sum of digits at odd places of the given number is Not divisible by the another given number k.
The Exit of the Program.

Below is the implementation:

# Give the number as user input using the int(input()) function and store it in a variable.
gvn_numb = int(input("Enter some random number = "))
#Give the other number k as user input using the int(input()) function and store it in another variable.
gvn_k = int(input("Enter some random number = "))
# Convert the given number to a string using the str() function and store it in
# another variable.
stringnum = str(gvn_numb)
# Create a list of digits say "digtslst" using map(),list(),int functions.
digtslst = list(map(int, stringnum))
# Take a variable say "od_sum" and initialize it with 0.
od_sum = 0
# Loop in the above list of digits until the length of the "digtslst" using the for loop.
for itr in range(len(digtslst)):
    # Check if the iterator value is odd or not using
    # the if conditional statement.
    if(itr % 2 != 0):
        # If the statement is true, then add the element of digits list at iterator value to
        # the "od_sum"  and store it in the same variable od_sum.
        od_sum += digtslst[itr]
# Check if the od_sum modulus given number k is equal to 0 or not using the if conditional
# statement.
if(od_sum % gvn_k == 0):
    # If the statement is true, then print "The sum of digits at odd places of the given
    # number is divisible by the another given number k.
    print("The sum of digits at odd places of the given number{", gvn_numb,
          "} is divisible by the another given number k{", gvn_k, "}")
else:
    # If the statement is false, then print "The sum of digits at odd places of the given
    # number is Not divisible by the another given number k.
    print("The sum of digits at odd places of the given number{", gvn_numb,
          "} is not divisible by the another given number k{", gvn_k, "}")

Output:

Enter some random number = 624351
Enter some random number = 3
The sum of digits at odd places of the given number{ 624351 } is divisible by the another given number k{ 3 }

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