Python Program to Convert Decimal Number to Binary String using Recursion

In the previous article, we have discussed Python Program to Convert Binary to Decimal using Recursion
Recursion:

Recursion is the process by which a function calls itself directly or indirectly, and the associated function is known as a recursive function. Certain issues can be addressed fairly easily using a recursive approach. Towers of Hanoi (TOH), Inorder /Preorder/Postorder Tree Traversals, DFS of Graph, and other analogous issues are examples.

Binary Code:

As previously stated, Binary Code is a Base-2 representation of a number. In Binary, all numbers are represented by simply two symbols: 0 and 1. Binary (also known as base-2) is a numerical system with only two digits: 0 and 1.

Given a binary string, the task is to convert the given decimal number to a binary string using recursion in Python.

Examples:

Example1:

Input:

Given binary number = 153

Output:

The decimal Equivalent of the given binary number { 153 } is : 10011001

Example2:

Input:

Given binary number = 408

Output:

The decimal Equivalent of the given binary number { 408 } is : 110011000

Program to Convert Decimal Number to Binary String using Recursion in Python

Below are the ways to convert the given decimal number to a binary string using recursion in Python:

Using Recursion (Static Input)
Using Recursion (User Input)

Method #1: Using Recursion (Static Input)

Approach:

Give the decimal number as static input and store it in a variable.
Create a recursive function to say deciToBinary() which accepts the decimal number as an argument and returns the binary equivalent of the given decimal number.
Inside the deciToBinary() function, Check if the decimal number is equal to 0 using the if conditional statement.
If it is true then return 0.
Else return (n% 2 + 10* deciToBinary(n // 2)) {Recursive logic}
Inside the main function pass the given decimal number as an argument to deciToBinary() which returns the
binary equivalent of the given decimal number.
Print the binary equivalent of the given decimal number.
The Exit of the Program.

Below is the implementation:

# Create a recursive function to say deciToBinary() which accepts
# the decimal number as an argument and returns the binary equivalent
# of the given decimal number.


def deciToBinary(decinumb):
    # Inside the deciToBinary() function,
    # Check if the decimal number is equal to 0 using the if conditional statement.
    if(decinumb == 0):
        # If it is true then return 0.
        return 0
    # Else return (n% 2 + 10* deciToBinary(n // 2)) {Recursive logic}
    return (decinumb % 2 + 10 * deciToBinary(decinumb // 2))


# Give the decimal number as static input and store it in a variable.
gvndecimalnumb = 153
# Inside the main function pass the given decimal number as an argument
# to deciToBinary() which returns the
# binary equivalent of the given decimal number.
resbinarynumbr = deciToBinary(gvndecimalnumb)
# Print the decimal equivalent of the given binary number.
print(
    'The decimal Equivalent of the given binary number {', gvndecimalnumb, '} is :', resbinarynumbr)

Output:

The decimal Equivalent of the given binary number { 153 } is : 10011001

Method #2: Using Recursion (User Input)

Approach:

Give the binary number as user input using the int(input()) function and store it in a variable.
Create a recursive function to say deciToBinary() which accepts the decimal number as an argument and returns the binary equivalent of the given decimal number.
Inside the deciToBinary() function, Check if the decimal number is equal to 0 using the if conditional statement.
If it is true then return 0.
Else return (n% 2 + 10* deciToBinary(n // 2)) {Recursive logic}
Inside the main function pass the given decimal number as an argument to deciToBinary() which returns the binary equivalent of the given decimal number.
Print the binary equivalent of the given decimal number.
The Exit of the Program.

Below is the implementation:

# Create a recursive function to say deciToBinary() which accepts
# the decimal number as an argument and returns the binary equivalent
# of the given decimal number.


def deciToBinary(decinumb):
    # Inside the deciToBinary() function,
    # Check if the decimal number is equal to 0 using the if conditional statement.
    if(decinumb == 0):
        # If it is true then return 0.
        return 0
    # Else return (n% 2 + 10* deciToBinary(n // 2)) {Recursive logic}
    return (decinumb % 2 + 10 * deciToBinary(decinumb // 2))


# Give the binary number as user input using the int(input()) function and store it in a variable.
gvndecimalnumb = int(input('Enter some random decimal number = '))
# Inside the main function pass the given decimal number as an argument
# to deciToBinary() which returns the
# binary equivalent of the given decimal number.
resbinarynumbr = deciToBinary(gvndecimalnumb)
# Print the decimal equivalent of the given binary number.
print(
    'The decimal Equivalent of the given binary number {', gvndecimalnumb, '} is :', resbinarynumbr)

Output:

Enter some random decimal number = 408
The decimal Equivalent of the given binary number { 408 } is : 110011000

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