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Given the number of rows of the diamond pattern, the task is to print the Hollow diamond star pattern in C, C++, and Python
Examples:
Example1:
Input:
given number of rows of diamond =6
Output:
*
* *
* *
* *
* *
* *
* *
* *
* *
* *
*
Example2:
Input:
given number of rows of diamond =10 given character to print ='^'
Output:
^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^
Program to Print Diamond Star Pattern in C, C++, and Python
Below are the ways to print Diamond Star Pattern in C, C++, and Python.
Method #1: Using For loop (Star Character)
Approach:
- Give the number of rows of the diamond pattern as static input and store it in a variable.
- Loop from 1 to the number of rows using For Loop.
- Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).
- Print the space character in the inner For loop.
- Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).
- If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print star character.
- Else print space character.
- After the end of the inner for Loops print the Newline Character.
- loop from the number of rows -1 to 0 in decreasing order using For loop.
- Loop from 1 to number of rows- iterator value of the parent loop using another For loop(Nested For loop)
- Print the space character in the inner For loop.
- Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).
- If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print star character.
- Else print space character.
- After the end of the inner for Loops print the Newline Character.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of rows as static input and store it in a variable.
diamondrows = 6
# Loop from 1 to the number of rows using For Loop.
for m in range(1, diamondrows+1):
# Loop from 1 to the number of rows -iterator value of the parent
# For loop using another For loop(Nested For loop).
for n in range(1, diamondrows - m + 1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 1 to the 2* iterator value of the parent For loop
# using another For loop(Nested For loop).
for l in range(1, (2 * m)):
# If the value of the iterator is equal to 1 or 2* iterator value
# of the parent loop -1 then print star character.
if l == 1 or l == m * 2 - 1:
print('*', end='')
# Else print space character.
else:
print(' ', end='')
# After the end of the inner for Loops print the Newline Character.
print()
# loop from number of rows -1 to 0 in decreasing order using For loop.
for m in range(diamondrows - 1, 0, -1):
# Loop from 1 to number of rows- iterator value
# of the parent loop using another For loop(Nested For loop)
for n in range(1, diamondrows - m + 1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 1 to the 2* iterator value of the parent For loop
# using another For loop(Nested For loop).
for l in range(1, (2 * m)):
# If the value of the iterator is equal to 1 or 2* iterator value
# of the parent loop -1 then print star character.
if l == 1 or l == m * 2 - 1:
print('*', end='')
# Else print space character.
else:
print(' ', end='')
# After the end of the inner for Loops print the Newline Character.
print(
Output:
*
* *
* *
* *
* *
* *
* *
* *
* *
* *
*
2) C++ Implementation
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows of the diamond pattern
// as static input and store it in a variable.
int diamondrows = 6;
char givencharacter = '*';
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
cout << givencharacter;
// Else print space character.
else
cout << " ";
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
// loop from number of rows -1 to 0 in decreasing order using For loop.
for (int m = diamondrows-1; m > 0; m--) {
//Loop from 1 to number of rows- iterator value
// of the parent loop using another For loop(Nested For loop)
for (int n = 1; n <= diamondrows-m; n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
cout << givencharacter;
// Else print space character.
else
cout << " ";
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
return 0;
}
Output:
*
* *
* *
* *
* *
* *
* *
* *
* *
* *
*
3) C Implementation
Below is the implementation:
#include <stdio.h>
int main()
{
char givencharacter = '*';
// Give the number of rows of the diamond pattern
// as static input and store it in a variable.
int diamondrows = 6;
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
printf("%c", givencharacter);
// Else print space character.
else
printf(" ");
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
// loop from number of rows -1 to 0 in decreasing order
// using For loop.
for (int m = diamondrows - 1; m > 0; m--) {
// Loop from 1 to number of rows- iterator value
// of the parent loop using another For loop(Nested
// For loop)
for (int n = 1; n <= diamondrows - m; n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
printf("%c", givencharacter);
// Else print space character.
else
printf(" ");
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
return 0;
}
Output:
*
* *
* *
* *
* *
* *
* *
* *
* *
* *
*
Method #2: Using For loop (User Character)
Approach:
- Give the number of rows of the diamond pattern as user input and store it in a variable.
- Give the character to print as user input and store it in a variable.
- Loop from 1 to the number of rows using For Loop.
- Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).
- Print the space character in the inner For loop.
- Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).
- If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print given character.
- Else print space character.
- After the end of the inner for Loops print the Newline Character.
- loop from the number of rows -1 to 0 in decreasing order using For loop.
- Loop from 1 to number of rows- iterator value of the parent loop using another For loop(Nested For loop)
- Print the space character in the inner For loop.
- Loop from 1 to the 2* iterator value of the parent For loop using another For loop(Nested For loop).
- If the value of the iterator is equal to 1 or 2* iterator value of the parent loop -1 then print given character.
- Else print space character.
- After the end of the inner for Loops print the Newline Character.
- The Exit of the Program.
1) Python Implementation
- Give the number of rows as user input using int(input()) and store it in a variable.
- Give the Character as user input using input() and store it in another variable.
Below is the implementation:
# Give the number of rows as user input using int(input()) and store it in a variable.
diamondrows = int(input(
'Enter some random number of rows = '))
# Give the Character as user input using input() and store it in another variable.
givencharacter = input('Enter some random character = ')
# Loop from 1 to the number of rows using For Loop.
for m in range(1, diamondrows+1):
# Loop from 1 to the number of rows -iterator value of the parent
# For loop using another For loop(Nested For loop).
for n in range(1, diamondrows - m + 1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 1 to the 2* iterator value of the parent For loop
# using another For loop(Nested For loop).
for l in range(1, (2 * m)):
# If the value of the iterator is equal to 1 or 2* iterator value
# of the parent loop -1 then print givencharacter .
if l == 1 or l == m * 2 - 1:
print(givencharacter, end='')
# Else print space character.
else:
print(' ', end='')
# After the end of the inner for Loops print the Newline Character.
print()
# loop from number of rows -1 to 0 in decreasing order using For loop.
for m in range(diamondrows - 1, 0, -1):
# Loop from 1 to number of rows- iterator value
# of the parent loop using another For loop(Nested For loop)
for n in range(1, diamondrows - m + 1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 1 to the 2* iterator value of the parent For loop
# using another For loop(Nested For loop).
for l in range(1, (2 * m)):
# If the value of the iterator is equal to 1 or 2* iterator value
# of the parent loop -1 then print givencharacter .
if l == 1 or l == m * 2 - 1:
print(givencharacter, end='')
# Else print space character.
else:
print(' ', end='')
# After the end of the inner for Loops print the Newline Character.
print()
Output:
Enter some random number of rows = 10
Enter some random character = ^
^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^
2) C++ Implementation
- Give the number of rows as user input using cin and store it in a variable.
- Give the Character as user input using cin and store it in another variable.
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows
// as user input using cin and store it in a
// variable.
int diamondrows;
char givencharacter;
cout << "Enter some random number of rows = " << endl;
cin >> diamondrows;
// Give the Character as user input using cin and store
// it in another variable.
cout << "Enter some random character = " << endl;
cin >> givencharacter;
cout << endl;
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
cout << givencharacter;
// Else print space character.
else
cout << " ";
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
// loop from number of rows -1 to 0 in decreasing order using For loop.
for (int m = diamondrows-1; m > 0; m--) {
//Loop from 1 to number of rows- iterator value
// of the parent loop using another For loop(Nested For loop)
for (int n = 1; n <= diamondrows-m; n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
cout << givencharacter;
// Else print space character.
else
cout << " ";
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
return 0;
}
Output:
Enter some random number of rows =
10
Enter some random character =
^
^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^
3) C Implementation
- Give the number of rows as user input using scanf and store it in a variable.
- Give the Character as user input using scanf and store it in another variable.
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows
// as user input using scanf and store it in a
// variable.
int diamondrows;
char givencharacter;
// Give the Character as user input using scanf and
// store it in another variable.
scanf("%d", &diamondrows);
scanf("%c", &givencharacter);
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
printf("%c", givencharacter);
// Else print space character.
else
printf(" ");
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
// loop from number of rows -1 to 0 in decreasing order
// using For loop.
for (int m = diamondrows - 1; m > 0; m--) {
// Loop from 1 to number of rows- iterator value
// of the parent loop using another For loop(Nested
// For loop)
for (int n = 1; n <= diamondrows - m; n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 1 to the 2* iterator value of the
// parent For loop
// using another For loop(Nested For loop).
for (int l = 1; l < (2 * m); l++) {
// If the value of the iterator is equal to 1 or
// 2* iterator value of the parent loop -1 then
// print givencharacter .
if (l == 1 || l == m * 2 - 1)
printf("%c", givencharacter);
// Else print space character.
else
printf(" ");
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
return 0;
}
Output:
10^
^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^ ^
^
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