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Given the number of rows of the diamond pattern, the task is to print the diamond star pattern in C, C++, and Python
Examples:
Example1:
Input:
given number of rows of diamond =5
Output:
*
***
*****
*******
*********
*******
*****
***
*
Example2:
Input:
given number of rows of diamond =7 given character to print ='$'
Output:
$
$$$
$$$$$
$$$$$$$
$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$
$$$$$$$
$$$$$
$$$
$
Program to Print Diamond Star Pattern in C, C++, and Python
Below are the ways to print Diamond Star Pattern in C, C++, and Python.
Method #1: Using For loop (Star Character)
Approach:
- Give the number of rows of the diamond pattern as static input and store it in a variable.
- Loop from 1 to the number of rows using For Loop.
- Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).
- Print the space character in the inner For loop.
- Loop from 0 to the 2* iterator value – 1 of the parent For loop using another For loop(Nested For loop).
- Print the star character.
- After the end of the inner for Loops print the Newline Character.
- Loop from 1 to the number of rows using For loop.
- Loop from 1 to iterator value of the parent For loop using another For loop(Nested For loop).
- Print the space character in the inner For loop.
- Loop from 1 to 2*(number of rows – iterator value of the parent for loop) using another For loop(Nested For loop).
- Print the star character.
- After the end of the inner for Loops print the Newline Character.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of rows of the diamond pattern as static input and store it in a variable.
diamondrows = 5
# Loop from 1 to the number of rows using For Loop.
for m in range(1, diamondrows+1):
# Loop from 1 to the number of rows -iterator value of the parent
# For loop using another For loop(Nested For loop).
for n in range(1, diamondrows - m + 1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 0 to the 2* iterator value - 1 of the parent For loop
# using another For loop(Nested For loop).
for l in range(0, (2 * m) - 1):
# Print the star character
print('*', end='')
# After the end of the inner for Loops print the Newline Character.
print()
# Loop from 1 to the number of rows using For loop.
for m in range(1, diamondrows):
# Loop from 1 to iterator value of the parent For loop
# using another For loop(Nested For loop).
for n in range(1, m+1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 1 to 2*(number of rows - iterator value of the parent for loop)
# using another For loop(Nested For loop).
for l in range(1, (2 * (diamondrows - m))):
# Print the star character
print('*', end='')
# After the end of the inner for Loops print the Newline Character.
print()
Output:
*
***
*****
*******
*********
*******
*****
***
*
2) C++ Implementation
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows of the diamond pattern
// as static input and store it in a variable.
int diamondrows = 5;
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 0 to the 2 * iterator value- 1 of the
// parent For loop using another For loop(Nested For
// loop).
for (int l = 0; l < ((2 * m) - 1); l++) {
// Print the star character
cout << "*";
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < diamondrows; m++) {
// Loop from 1 to iterator value of the parent For
// loop using another For loop(Nested For loop).
for (int n = 1; n <= m; n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 1 to 2* (number of rows- iterator value
// of the parent for loop) using another For
// loop(Nested For loop).
for (int l = 1; l < (2 * (diamondrows - m)); l++) {
// Print the star character
cout << "*";
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
return 0;
}
Output:
*
***
*****
*******
*********
*******
*****
***
*
3) C Implementation
Below is the implementation:
#include <stdio.h>
int main()
{ // Give the number of rows of the diamond pattern
// as static input and store it in a variable.
int diamondrows = 5;
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 0 to the 2 * iterator value- 1 of the
// parent For loop using another For loop(Nested For
// loop).
for (int l = 0; l < ((2 * m) - 1); l++) {
// Print the star character
printf("*");
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < diamondrows; m++) {
// Loop from 1 to iterator value of the parent For
// loop using another For loop(Nested For loop).
for (int n = 1; n <= m; n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 1 to 2* (number of rows- iterator value
// of the parent for loop) using another For
// loop(Nested For loop).
for (int l = 1; l < (2 * (diamondrows - m)); l++) {
// Print the star character
printf("*");
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
return 0;
}
Output:
*
***
*****
*******
*********
*******
*****
***
*
Method #2: Using For loop (User Character)
Approach:
- Give the number of rows of the diamond pattern as user input and store it in a variable.
- Give the character to print as user input and store it in a variable.
- Loop from 1 to the number of rows using For Loop.
- Loop from 1 to the number of rows -iterator value of the parent For loop using another For loop(Nested For loop).
- Print the space character in the inner For loop.
- Loop from 0 to the 2* iterator value – 1 of the parent For loop using another For loop(Nested For loop).
- Print the given character.
- After the end of the inner for Loops print the Newline Character.
- Loop from 1 to the number of rows using For loop.
- Loop from 1 to iterator value of the parent For loop using another For loop(Nested For loop).
- Print the space character in the inner For loop.
- Loop from 1 to 2*(number of rows – iterator value of the parent for loop) using another For loop(Nested For loop).
- Print the given character.
- After the end of the inner for Loops print the Newline Character.
- The Exit of the Program.
1) Python Implementation
- Give the number of rows as user input using int(input()) and store it in a variable.
- Give the Character as user input using input() and store it in another variable.
Below is the implementation:
# Give the number of rows as user input using int(input()) and store it in a variable.
diamondrows = int(input(
'Enter some random number of rows = '))
# Give the Character as user input using input() and store it in another variable.
givencharacter = input('Enter some random character = ')
# Loop from 1 to the number of rows using For Loop.
for m in range(1, diamondrows+1):
# Loop from 1 to the number of rows -iterator value of the parent
# For loop using another For loop(Nested For loop).
for n in range(1, diamondrows - m + 1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 0 to the 2* iterator value - 1 of the parent For loop
# using another For loop(Nested For loop).
for l in range(0, (2 * m) - 1):
# Print the given character
print(givencharacter, end='')
# After the end of the inner for Loops print the Newline Character.
print()
# Loop from 1 to the number of rows using For loop.
for m in range(1, diamondrows):
# Loop from 1 to iterator value of the parent For loop
# using another For loop(Nested For loop).
for n in range(1, m+1):
# Print the space character in the inner For loop.
print(end=' ')
# Loop from 1 to 2*(number of rows - iterator value of the parent for loop)
# using another For loop(Nested For loop).
for l in range(1, (2 * (diamondrows - m))):
# Print the given character
print(givencharacter, end='')
# After the end of the inner for Loops print the Newline Character.
print()
Output:
Enter some random number of rows = 7
Enter some random character = $
$
$$$
$$$$$
$$$$$$$
$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$
$$$$$$$
$$$$$
$$$
$
2) C++ Implementation
- Give the number of rows as user input using cin and store it in a variable.
- Give the Character as user input using cin and store it in another variable.
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows
// as user input using cin and store it in a
// variable.
int diamondrows;
char givencharacter;
cout << "Enter some random number of rows = " << endl;
cin >> diamondrows;
// Give the Character as user input using cin and store
// it in another variable.
cout << "Enter some random character = " << endl;
cin >> givencharacter;
cout << endl;
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 0 to the 2 * iterator value- 1 of the
// parent For loop using another For loop(Nested For
// loop).
for (int l = 0; l < ((2 * m) - 1); l++) {
// Print the given character
cout << givencharacter;
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < diamondrows; m++) {
// Loop from 1 to iterator value of the parent For
// loop using another For loop(Nested For loop).
for (int n = 1; n <= m; n++) {
// Print the space character in the inner For
// loop.
cout << " ";
}
// Loop from 1 to 2* (number of rows- iterator value
// of the parent for loop) using another For
// loop(Nested For loop).
for (int l = 1; l < (2 * (diamondrows - m)); l++) {
// Print the given character
cout << givencharacter;
}
// After the end of the inner for Loops print the
// Newline Character.
cout << endl;
}
return 0;
}
Output:
Enter some random number of rows =
7
Enter some random character =
$
$
$$$
$$$$$
$$$$$$$
$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$
$$$$$$$
$$$$$
$$$
$
3) C Implementation
- Give the number of rows as user input using scanf and store it in a variable.
- Give the Character as user input using scanf and store it in another variable.
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows
// as user input using scanf and store it in a
// variable.
int diamondrows;
char givencharacter;
// Give the Character as user input using scanf and
// store it in another variable.
scanf("%d", &diamondrows);
scanf("%c", &givencharacter);
// Loop from 1 to the number of rows using For Loop.
for (int m = 1; m <= diamondrows; m++) {
// Loop from 1 to the number of rows- iterator value
// of the parent For loop using another For
// loop(Nested For loop).
for (int n = 1; n <= (diamondrows - m); n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 0 to the 2 * iterator value- 1 of the
// parent For loop using another For loop(Nested For
// loop).
for (int l = 0; l < ((2 * m) - 1); l++) {
// Print the given character
printf("%c", givencharacter);
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < diamondrows; m++) {
// Loop from 1 to iterator value of the parent For
// loop using another For loop(Nested For loop).
for (int n = 1; n <= m; n++) {
// Print the space character in the inner For
// loop.
printf(" ");
}
// Loop from 1 to 2* (number of rows- iterator value
// of the parent for loop) using another For
// loop(Nested For loop).
for (int l = 1; l < (2 * (diamondrows - m)); l++) {
// Print the givencharacter
printf("%c", givencharacter);
}
// After the end of the inner for Loops print the
// Newline Character.
printf("\n");
}
return 0;
}
Output:
7$
$
$$$
$$$$$
$$$$$$$
$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$$$$$
$$$$$$$$$$$
$$$$$$$$$
$$$$$$$
$$$$$
$$$
$
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