# Python Program to Print Number Reduction Pattern

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Given the number of rows, the task is to print Number Reduction Pattern in C, C++, and Python

Examples:

Example1:

Input:

Given number of rows = 4

Output:

1 2 3 4
2 3 4
3 4
4

Example2:

Input:

Given number of rows = 14

Output:

1 2 3 4 5 6 7 8 9 10 11 12 13 14
2 3 4 5 6 7 8 9 10 11 12 13 14
3 4 5 6 7 8 9 10 11 12 13 14
4 5 6 7 8 9 10 11 12 13 14
5 6 7 8 9 10 11 12 13 14
6 7 8 9 10 11 12 13 14
7 8 9 10 11 12 13 14
8 9 10 11 12 13 14
9 10 11 12 13 14
10 11 12 13 14
11 12 13 14
12 13 14
13 14
14


## Program to Print Number Reduction Pattern in C, C++, and Python

Below are the ways to print Number Reduction Pattern in C, C++, and Python

### Method #1: Using For Loop (Static Input)

Approach:

• Give the number of rows as static input and store it in a variable.
• Loop from 0 to the number of rows using For loop.
• Loop from iterator value of the parent For loop +1 to the number of rows using another for loop(Nested For loop).
• Print the iterator value of the inner for loop.
• Print the Newline character after the end of the inner loop.
• The Exit of the Program.

1) Python Implementation

Below is the implementation:

# Give the number of rows as static input and store it in a variable.
numbrrows = 9
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
# Loop from iterator value of the parent For loop +1 to
# the number of rows using another for loop(Nested For loop).
for n in range(m + 1, numbrrows+1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()


Output:

1 2 3 4 5 6 7 8 9
2 3 4 5 6 7 8 9
3 4 5 6 7 8 9
4 5 6 7 8 9
5 6 7 8 9
6 7 8 9
7 8 9
8 9
9

2) C++ Implementation

Below is the implementation:

#include <iostream>
using namespace std;

int main()
{

// Give the number of rows as static input and store it
// in a variable.
int numbrrows = 10;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}

Output:

1 2 3 4 5 6 7 8 9 10
2 3 4 5 6 7 8 9 10
3 4 5 6 7 8 9 10
4 5 6 7 8 9 10
5 6 7 8 9 10
6 7 8 9 10
7 8 9 10
8 9 10
9 10
10

3) C Implementation

Below is the implementation:

#include <stdio.h>

int main()
{

// Give the number of rows as static input and store it
// in a variable.
int numbrrows = 14;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}

Output:

1 2 3 4 5 6 7 8 9 10 11 12 13 14
2 3 4 5 6 7 8 9 10 11 12 13 14
3 4 5 6 7 8 9 10 11 12 13 14
4 5 6 7 8 9 10 11 12 13 14
5 6 7 8 9 10 11 12 13 14
6 7 8 9 10 11 12 13 14
7 8 9 10 11 12 13 14
8 9 10 11 12 13 14
9 10 11 12 13 14
10 11 12 13 14
11 12 13 14
12 13 14
13 14
14


### Method #2: Using For Loop (User Input)

Approach:

• Give the number of rows as user input and store it in a variable.
• Loop from 0 to the number of rows using For loop.
• Loop from iterator value of the parent For loop +1 to the number of rows using another for loop(Nested For loop).
• Print the iterator value of the inner for loop.
• Print the Newline character after the end of the inner loop.
• The Exit of the Program.

1) Python Implementation

Give the number of rows as user input using int(input()) and store it in a variable.

Below is the implementation:

# Give the number of rows as user input using int(input()) and store it in a variable.
numbrrows = int(input('Enter some random number of rows = '))
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
# Loop from iterator value of the parent For loop +1 to
# the number of rows using another for loop(Nested For loop).
for n in range(m + 1, numbrrows+1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()


Output:

Enter some random number of rows = 6
1 2 3 4 5 6
2 3 4 5 6
3 4 5 6
4 5 6
5 6
6

2) C++ Implementation

Give the number of rows as user input using cin and store it in a variable.

Below is the implementation:

#include <iostream>
using namespace std;
int main()
{

// Give the number of rows as user input using
// int(input()) and store it in a variable.
int numbrrows;
cin >> numbrrows;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}

return 0;
}

Output:

4
1 2 3 4
2 3 4
3 4
4

3) C Implementation

Give the number of rows as user input using scanf and store it in a variable.

Below is the implementation:

#include <math.h>
#include <stdio.h>
int main()
{

// Give the number of rows as user input using scanf and
// store it in a variable.
int numbrrows;
scanf("%d", &numbrrows);
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}

Output:

4
1 2 3 4
2 3 4
3 4
4

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