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Given the number of rows and a number, the task is to print a square number pattern in C, C++, and Python.
Examples:
Example1:
Input:
given number of sides = 5 given element of square =3
Output:
3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3
Example2:
Input:
given number of sides = 7 given element of square =9
Output:
9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9
Program to Print Square Number Pattern in C, C++, and Python
Below are the ways to print square number pattern in C, C++, and Python.
Method #1: Using For loop (Element is of static input)
Approach:
- Give the number of sides of the square as static input and store it in a variable.
- Using Nested For loops print the square pattern.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of sides of the square as static input and store it in a variable.
sidesnum = 10
# Using Nested For loops print the square pattern.
for m in range(sidesnum):
for n in range(sidesnum):
print('1', end=' ')
print()
Output:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
2) C++ Implementation
Below is the implementation:
#include <iostream>
using namespace std;
int main(void)
{
// Give the number of sides of the square as static
// input
// and store it in a variable.
int sidesnum = 7;
// Using Nested For loops print the square pattern.
for (int m = 1; m <= sidesnum; m++) {
for (int n = 1; n <= sidesnum; n++) {
cout << "1 ";
}
cout << endl;
}
return 0;
}
Output:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
3) C Implementation
Below is the implementation:
#include<stdio.h>
int main()
{
// Give the number of sides of the square as static input
// and store it in a variable.
int sidesnum = 7, m, n;
// Using Nested For loops print the square pattern.
for(m = 0; m < sidesnum; m++)
{
for(n = 0; n < sidesnum; n++)
{
printf("1 ");
}
printf("\n");
}
return 0;
}
Output:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
Method #2: Using For loop (Element is of User input)
Approach:
- Give the number of sides of the square as user input and store it in a variable.
- Give the Element as user input and store it in another variable.
- Using Nested For loops print the square pattern.
- The Exit of the Program.
1) Python Implementation
- Give the number of sides of the square as user input using int(input()) and store it in a variable.
- Give the Element as user input using int(input()) and store it in another variable.
Below is the implementation:
# Give the number of sides of the square as user input using int(input()) and store it in a variable.
# Give the Element as user input using int(input()) and store it in another variable.
sidesnum = int(input('Enter some random number of sides = '))
eleme = int(input('Enter some random element = '))
# Using Nested For loops print the square pattern.
for m in range(sidesnum):
for n in range(sidesnum):
print(eleme, end=' ')
print()
Output:
Enter some random number of sides = 11 Enter some random element = 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23 23
2) C++Implementation
- Give the number of sides of the square as user input using cin and store it in a variable.
- Give the Element as user input using cin and store it in another variable.
Below is the implementation:
#include <iostream>
using namespace std;
int main(void)
{
int sidesnum, eleme;
// Give the number of sides of the square as user input
// using cin and
// store it in a variable.
cin >> sidesnum;
// Give the Element as user input using cin and store it
// in another variable.
cin >> eleme;
// Using Nested For loops print the square pattern.
for (int m = 1; m <= sidesnum; m++) {
for (int n = 1; n <= sidesnum; n++) {
cout << eleme << " ";
}
cout << endl;
}
return 0;
}
3) C Implementation
- Give the number of sides of the square as user input using scanf and store it in a variable.
- Give the Element as user input using scanf and store it in another variable.
Below is the implementation:
#include<stdio.h>
int main()
{ int sidesnum, eleme;
// Give the number of sides of the square as user input
// using cin and
// store it in a variable.
scanf("%d",&sidesnum);
// Give the Element as user input using cin and store it
// in another variable.
scanf("%d",&eleme);
// Using Nested For loops print the square pattern.
for (int m = 1; m <= sidesnum; m++) {
for (int n = 1; n <= sidesnum; n++) {
printf("%d ",eleme);
}
printf("\n");
}
}
Output:
22 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
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