Python Program to Determine Whether a Given Number is Even or Odd Recursively

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Recursion:

Recursion is the process by which a function calls itself directly or indirectly, and the associated function is known as a recursive function. Certain issues can be addressed fairly easily using a recursive approach. Towers of Hanoi (TOH), Inorder /Preorder/Postorder Tree Traversals, DFS of Graph, and other analogous issues are examples.

Given a number the task is to check whether the given number is even number or odd number using recursive approach in Python.

Examples:

Example1:

Input:

Enter some random number = 215

Output:

The given number 215 is odd

Example2:

Input:

Enter some random number = 628

Output:

The given number 628 is even

Program to Determine Whether a Given Number is Even or Odd Recursively

Below are the ways to check whether the given number is even or odd recursively :

Using Recursion(Static Input)
Using Recursion(User Input)

1)Using Recursion(Static Input)

Approach:

Give the number as static input.
Pass the number to a recursive function as an argument.
Define the base condition as an integer less than two.
Otherwise, use the number -2 to invoke the function recursively.
Then return the result and determine whether the number is even or odd.
The final result should be printed.
Exit of program.

Below is the implementation:

# function which returns true if the given number
# is evennum or oddnum using recursoive approach


def checkPrimeRecursion(numb):
  # Defining the base condition as an integer less than two.
    if (numb < 2):
      # Then return the result and determine whether the number is even or odd.
        return (numb % 2 == 0)
    # Otherwise, use the number -2 to invoke the function recursively.
    return (checkPrimeRecursion(numb - 2))


# Give the number as static input.
numb = 729
# passing the given number to checkPrimeRecursion
# if the returned value is true then it is even number
if(checkPrimeRecursion(numb)):
    print("The given number", numb, "is even")
# if the returned value is false then it is odd number
else:
    print("The given number", numb, "is odd")

Output:

The given number 729 is odd

Explanation:

User must give the number as static input and store it in a variable.
A recursive function is given the number as an argument.
The basic requirement is that the number be less than two.
Otherwise, the function is called recursively with a number less than two.
The outcome is returned, and an if statement is used to determine whether the integer is odd or even.
The final result is printed.

2)Using Recursion(User Input)

Approach:

Enter some random number as user input using int(input()) function.
Pass the number to a recursive function as an argument.
Define the base condition as an integer less than two.
Otherwise, use the number -2 to invoke the function recursively.
Then return the result and determine whether the number is even or odd.
The final result should be printed.
Exit of program.

Below is the implementation:

# function which returns true if the given number
# is evennum or oddnum using recursoive approach


def checkPrimeRecursion(numb):
  # Defining the base condition as an integer less than two.
    if (numb < 2):
      # Then return the result and determine whether the number is even or odd.
        return (numb % 2 == 0)
    # Otherwise, use the number -2 to invoke the function recursively.
    return (checkPrimeRecursion(numb - 2))


# Give the number as static input.
numb = int(input('Enter some random number = '))
# passing the given number to checkPrimeRecursion
# if the returned value is true then it is even number
if(checkPrimeRecursion(numb)):
    print("The given number", numb, "is even")
# if the returned value is false then it is odd number
else:
    print("The given number", numb, "is odd")

Output:

Enter some random number = 215
The given number 215 is odd

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