Given the numbers N and K, the task is to print the first K Digits of 1/N in Python.

**Examples:**

**Example1:**

**Input:**

Given numb=9 Given k=3

**Output:**

The first [3] digits in the given number [ 9 ] is :111

**Example2:**

**Input:**

Given numb=1 Given k=7

**Output:**

The first [7] digits in the given number [ 1 ] is :00000001

## Program to Print First k Digits of 1/N where N is a Positive Integer in Python

Below are the ways to print the first K Digits of 1/N in Python.

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**Algorithm:**

Initially, enter the user’s n-th number. Then enter the number k, which represents the number of digits. You will now know how to develop the code so that it writes the first k digits to the output after receiving inputs. So we use to divide and multiply in the code. We divide 1 by n and get a floating number less than 1. Then we multiply k by 10 and then multiply by that floating number before converting the complete result to an integer and printing that integer to get the first k digits of 1/n.

If n is equal to 1, this will not work since 1/1 is no longer a floating number, and we are not going to convert y into an integer because it is already an integer, but we are going to convert it into a string and reverse that string. That string should be printed.

### Method #1: Using If Statement (Static Input)

**Approach:**

- GIve the numbers n and k as static input and store them in two separate variables.
- Calculate the value of 1/n and store it in a variable say
**divval**. - Calculate the value of 10 power k using the ** operator and store it in a variable say
**powerval**. - Calculate the integer value of the product of
**divval**and**powerval**and store it in another variable say**resval**. - Check if the value of n is equal to 1 or not using the If conditional Statement.
- Convert the
**resvalÂ**to string using the str() function and store it in the same variable. - Print the
**resval**in reverse order using slicing. - If the
**“IF”**conditional statement is false then print the value of**resval**. - The Exit of the Program.

**Below is the implementation:**

# GIve the numbers n and k as static input and store them in two separate variables. numb = 9 k = 3 # Calculate the value of 1/n and store it in a variable say divval. divval = 1/numb # Calculate the value of 10 power k using the ** operator # and store it in a variable say powerval. powerval = 10**k # Calculate the integer value of the product of divval and powerval # and store it in another variable say resval. resval = int(divval*powerval) # Check if the value of n is equal to 1 or not # using the If conditional Statement. if(numb == 1): # Convert the resvalÂ to string using the str() function # and store it in the same variable. resval = str(resval) # Print the resval in reverse order using slicing. print("The first ["+str(k)+"] digits in the given number [ " + str(numb)+" ] is :"+str(resval[::-1])) # If the "IF" conditional statement is false then print the value of resval. else: print("The first ["+str(k)+"] digits in the given number [ " + str(numb)+" ] is :"+str(resval))

**Output:**

The first [3] digits in the given number [ 9 ] is :111

### Method #2: Using If Statement (User Input)

**Approach:**

- GIve the numbers n and k as user input using map(),int(),split() functions.
- Store them in two separate variables.
- Calculate the value of 1/n and store it in a variable say
**divval**. - Calculate the value of 10 power k using the ** operator and store it in a variable say
**powerval**. - Calculate the integer value of the product of
**divval**and**powerval**and store it in another variable say**resval**. - Check if the value of n is equal to 1 or not using the If conditional Statement.
- Convert the
**resvalÂ**to string using the str() function and store it in the same variable. - Print the
**resval**in reverse order using slicing. - If the
**“IF”**conditional statement is false then print the value of**resval**. - The Exit of the Program.

**Below is the implementation:**

# GIve the numbers n and k as user input using map(),int(),split() functions. # Store them in two separate variables. numb, k = map(int, input( 'Enter some random values of numb and k separated by spaces = ').split()) # Calculate the value of 1/n and store it in a variable say divval. divval = 1/numb # Calculate the value of 10 power k using the ** operator # and store it in a variable say powerval. powerval = 10**k # Calculate the integer value of the product of divval and powerval # and store it in another variable say resval. resval = int(divval*powerval) # Check if the value of n is equal to 1 or not # using the If conditional Statement. if(numb == 1): # Convert the resvalÂ to string using the str() function # and store it in the same variable. resval = str(resval) # Print the resval in reverse order using slicing. print("The first ["+str(k)+"] digits in the given number [ " + str(numb)+" ] is :"+str(resval[::-1])) # If the "IF" conditional statement is false then print the value of resval. else: print("The first ["+str(k)+"] digits in the given number [ " + str(numb)+" ] is :"+str(resval))

**Output:**

Enter some random values of numb and k separated by spaces = 1 7 The first [7] digits in the given number [ 1 ] is :00000001

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