Given a binary string, the task is to flip the bits in the given binary string in Python.

Examples:

Example1:

Input:

Given Binary string =1101010001001

Output:

The given binary string before flipping bits is [ 1101010001001 ]
The given binary string after flipping bits is [ 0010101110110 ]

Example2:

Input:

Given Binary string =00110011111

Output:

The given binary string before flipping bits is [ 00110011111 ]
The given binary string after flipping bits is [ 11001100000 ]

Program to Flipping the Binary Bits in Python

Below are the ways to flip the bits in the given binary string in Python.

• Using For loop(Static Input)
• Using For loop(User Input)
• Using replace() function (Static Input)
• Using replace() function (User Input)

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Method #1: Using For Loop (Static Input)

Approach:

• Give the binary string as static input and store it in a variable.
• Take an empty string(say flipbinary) which is the result after flipping the bits and initialize its value to a null string using “”.
• Traverse the given binary string using For loop.
• If the bit is 1 then concatenate the flipbinary with 0.
• Else concatenate the flipbinary with 1.
• Print the modified binary string after flipping the bits.
• The Exit of the Program.

Below is the implementation:

# Give the binary string as static input and store it in a variable.
gvnbinstring = '1101010001001'
# Take an empty string(say flipbinary) which is the result after flipping the bits
# and initialize its value to a null string using "".
flipbinary = ""
# Traverse the given binary string using For loop.
for bitval in gvnbinstring:
    # If the bit is 1 then concatenate the flipbinary with 0.
    if bitval == '1':
        flipbinary += '0'
    # Else concatenate the flipbinary with 1.
    else:
        flipbinary += '1'
# Print the modified binary string after flipping the bits.
print('The given binary string before flipping bits is [', gvnbinstring, ']')
print('The given binary string after flipping bits is [', flipbinary, ']')

Output:

The given binary string before flipping bits is [ 1101010001001 ]
The given binary string after flipping bits is [ 0010101110110 ]

Method #2: Using For Loop (User Input)

Approach:

• Give the binary string as user input using input() and store it in a variable.
• Take an empty string(say flipbinary) which is the result after flipping the bits and initialize its value to a null string using “”.
• Traverse the given binary string using For loop.
• If the bit is 1 then concatenate the flipbinary with 0.
• Else concatenate the flipbinary with 1.
• Print the modified binary string after flipping the bits.
• The Exit of the Program.

Below is the implementation:

# Give the binary string as user input using input() and store it in a variable.
gvnbinstring = input('Enter some random binary string = ')
# Take an empty string(say flipbinary) which is the result after flipping the bits
# and initialize its value to a null string using "".
flipbinary = ""
# Traverse the given binary string using For loop.
for bitval in gvnbinstring:
    # If the bit is 1 then concatenate the flipbinary with 0.
    if bitval == '1':
        flipbinary += '0'
    # Else concatenate the flipbinary with 1.
    else:
        flipbinary += '1'
# Print the modified binary string after flipping the bits.
print('The given binary string before flipping bits is [', gvnbinstring, ']')
print('The given binary string after flipping bits is [', flipbinary, ']')

Output:

Enter some random binary string = 0011100110101010
The given binary string before flipping bits is [ 0011100110101010 ]
The given binary string after flipping bits is [ 1100011001010101 ]

Method #3: Using replace() function (Static Input)

Approach:

• Give the binary string as static input and store it in a variable.
• Replace all 1’s present in the given binary string with some random character like p.
• Replace all 0’s present in the given binary string with 1.
• Replace all p’s present in the given binary string with 0.
• Here ‘p’ acts as a temporary variable.
• Print the modified binary string after flipping the bits.
• The Exit of the Program.

Below is the implementation:

# Give the binary string as static input and store it in a variable.
gvnbinstring = '1101010001001'

# Replace all 1's present in the given binary string
# with some random character like p.
flipbinary = gvnbinstring.replace('1', 'p')
# Replace all 0's present in the given
# binary string with 1.
flipbinary = flipbinary.replace('0', '1')
# Replace all p's present in the given
# binary string with 0.
# Here 'p' acts as a temporary variable.
flipbinary = flipbinary.replace('p', '0')
# Print the modified binary string after flipping the bits.
print('The given binary string before flipping bits is [', gvnbinstring, ']')
print('The given binary string after flipping bits is [', flipbinary, ']')

Output:

The given binary string before flipping bits is [ 1101010001001 ]
The given binary string after flipping bits is [ 0010101110110 ]

Method #4: Using replace() function (User Input)

Approach:

• Give the binary string as user input using input() and store it in a variable.
• Replace all 1’s present in the given binary string with some random character like p.
• Replace all 0’s present in the given binary string with 1.
• Replace all p’s present in the given binary string with 0.
• Here ‘p’ acts as a temporary variable.
• Print the modified binary string after flipping the bits.
• The Exit of the Program.

Below is the implementation:

# Give the binary string as user input using input() and store it in a variable.
gvnbinstring = input('Enter some random binary string = ')

# Replace all 1's present in the given binary string
# with some random character like p.
flipbinary = gvnbinstring.replace('1', 'p')
# Replace all 0's present in the given
# binary string with 1.
flipbinary = flipbinary.replace('0', '1')
# Replace all p's present in the given
# binary string with 0.
# Here 'p' acts as a temporary variable.
flipbinary = flipbinary.replace('p', '0')
# Print the modified binary string after flipping the bits.
print('The given binary string before flipping bits is [', gvnbinstring, ']')
print('The given binary string after flipping bits is [', flipbinary, ']')

Output:

Enter some random binary string = 00110011111
The given binary string before flipping bits is [ 00110011111 ]
The given binary string after flipping bits is [ 11001100000 ]

Related Programs:

• python program to find the total number of bits needed to be flipped
• python program to find the factorial of a number
• python program to find the largest among three numbers
• python program to display the multiplication table
• python program to find the sum of natural numbers
• python program to compute the power of a number
• python program to count the number of each vowel

Given the upper limit range, the task is to print all the prime numbers in the given range in Python.

Examples:

Example1:

Input:

given number = 95

Output:

The prime numbers from 2 to upper limit [ 95 ] :
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89

Example2:

Input:

given number = 52

Output:

Enter some random upper limit range = 52
The prime numbers from 2 to upper limit [ 52 ] :
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47

Python Program to Print all the Prime Numbers within a Given Range

There are several ways to print all the prime numbers from 2 to the upper limit range some of them are:

• Using for loop(Static Input)
• Using for loop(User Input )

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Method #1:Using for loop(Static Input)

Approach:

• Give the number as static input and store it in a variable.
• Set the first for loop to have a range of 2 to the upper limit range.
• Take a temporary variable which is the count variable and initialize it to zero.
• Allow the second for loop to have a range of 2 to half the number (excluding 1 and the number itself).
• Then, using the if statement, determine the number of divisors and increment the count variable each time.
• The number is prime if the number of divisors is lower than or equal to zero.
• Prime numbers till the given upper limit range are printed.
• The Exit of the Program.

Below is the implementation:

# Give the number as static input and store it in a variable.
givenNumbr = 95
print('The prime numbers from 2 to upper limit [', givenNumbr, '] :')
# Set the first for loop to have a range of 2 to the upper limit range.
for valu in range(2, givenNumbr+1):
  # Take a temporary variable which is the count variable and initialize it to zero.
    cntvar = 0
    # Allow the second for loop to have a range of 2 to
    # half the number (excluding 1 and the number itself).
    for divi in range(2, valu//2+1):
      # Then, using the if statement, determine the number of divisors
      # and increment the count variable each time.
        if(valu % divi == 0):
            cntvar = cntvar+1
    # The number is prime if the number of divisors is lower than or equal to zero.
    if(cntvar <= 0):
        print(valu, end=' ')

Output:

The prime numbers from 2 to upper limit [ 95 ] :
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89

All the prime numbers till the upper limit range are printed.

Method #2:Using for loop(User Input)

Approach:

• Give the number as user input with the help of the int(input()) function and store it in a variable.
• Set the first for loop to have a range of 2 to the upper limit range.
• Take a temporary variable which is the count variable and initialize it to zero.
• Allow the second for loop to have a range of 2 to half the number (excluding 1 and the number itself).
• Then, using the if statement, determine the number of divisors and increment the count variable each time.
• The number is prime if the number of divisors is lower than or equal to zero.
• Prime numbers till the given upper limit range are printed.
• The Exit of the Program.

Below is the implementation:

# Give the number as user input with the help
# of the int(input()) function and store it in a variable.
givenNumbr = int(input('Enter some random upper limit range = '))
print('The prime numbers from 2 to upper limit [', givenNumbr, '] :')
# Set the first for loop to have a range of 2 to the upper limit range.
for valu in range(2, givenNumbr+1):
  # Take a temporary variable which is the count variable and initialize it to zero.
    cntvar = 0
    # Allow the second for loop to have a range of 2 to
    # half the number (excluding 1 and the number itself).
    for divi in range(2, valu//2+1):
      # Then, using the if statement, determine the number of divisors
      # and increment the count variable each time.
        if(valu % divi == 0):
            cntvar = cntvar+1
    # The number is prime if the number of divisors is lower than or equal to zero.
    if(cntvar <= 0):
        print(valu, end=' ')

Output:

Enter some random upper limit range = 52
The prime numbers from 2 to upper limit [ 52 ] :
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47

Explanation:

• The user must enter the range’s upper limit and save it in a separate variable.
• The first for loop runs until the user enters an upper limit.
• The count variable is initially set to 0.
• Because the for loop runs from 2 to half of the number, 1 and the number itself is not considered divisors.
• If the remainder is equal to zero, the if statement looks for the number’s divisors.
• The count variable counts the number of divisors, and if the count is less than or equal to zero, the integer is prime.
• If the count exceeds zero, the integer is not prime.
• All the prime numbers till the upper limit range are printed.

Related Programs:

• Python Program to Print all Numbers in a Range Divisible by a Given Number
• Python Program to Print Odd Numbers Within a Given Range
• Python Program to Read a Text File and Print all the Numbers Present in the Text File
• Python Program to Read Print Prime Numbers in a Range using Sieve of Eratosthenes
• Python Program to Find all Numbers in a Range which are Perfect Squares and Sum of all Digits in the Number is Less than 10
• Python Program to Calculate the Average of Numbers in a Given List
• Python Program to Find Those Numbers which are Divisible by 7 and Multiple of 5 in a Given Range of Numbers

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If we examine closely at this problem, we can see that the concept of “loop” is to track some counter value, such as “i=0″ till I = higher”. So, if we aren’t permitted to use loops, how can we track something in Python?
One option is to use ‘recursion,’ however we must be careful with the terminating condition. Here’s a solution that uses recursion to output numbers.

Examples:

Example1:

Input:

Enter some upper limit range = 11

Output:

The numbers from 1 to 11 without using loops : 
1
2
3
4
5
6
7
8
9
10
11

Example2:

Input:

Enter some upper limit range = 28

Output:

The numbers from 1 to 28 without using loops : 
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28

Program to Print Numbers in a Range (1,upper) Without Using any Loops/Recursive Approach

Below are the ways to print all the numbers in the range from 1 to upper without using any loops or by using recursive approach.

• Using Recursive function(Static Input)
• Using Recursive function(User Input)

Method #1:Using Recursive function(Static Input)

Approach:

• Give the upper limit range using static input.
• Create a recursive function.
• Create a basic case for that function in when the integer is greater than zero.
• If the number is more than zero, call the function again with the input set to the number -1.
• Print the number.
• Exit of program.

Below is the implementation:

# function which prints numbers from 1 to gievn upper limit range
# without loop/by using recursion


def printNumbers(upper_limit):
  # checking if th upper limit value is greater than 0 using if statement
    if(upper_limit > 0):
      # If the number is more than zero, call the function again with
      # the input set to the number -1.
        printNumbers(upper_limit-1)
        # Print the upper limit
        print(upper_limit)


# giveen upper limt range
upper_limit = 28
print('The numbers from 1 to', upper_limit, 'without using loops : ')
# passing the given upper limit range to printNumbers
printNumbers(upper_limit)

Output:

The numbers from 1 to 28 without using loops : 
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28

Method #2:Using Recursive function(User Input)

Approach:

• Scan the upper limit range using int(input()).
• Create a recursive function.
• Create a basic case for that function in when the integer is greater than zero.
• If the number is more than zero, call the function again with the input set to the number -1.
• Print the number.
• Exit of program.

Below is the implementation:

# function which prints numbers from 1 to gievn upper limit range
# without loop/by using recursion


def printNumbers(upper_limit):
  # checking if th upper limit value is greater than 0 using if statement
    if(upper_limit > 0):
      # If the number is more than zero, call the function again with
      # the input set to the number -1.
        printNumbers(upper_limit-1)
        # Print the upper limit
        print(upper_limit)


# giveen upper limt range
upper_limit = int(input('Enter some upper limit range = '))
print('The numbers from 1 to', upper_limit, 'without using loops : ')
# passing the given upper limit range to printNumbers
printNumbers(upper_limit)

Output:

Enter some upper limit range = 11
The numbers from 1 to 11 without using loops : 
1
2
3
4
5
6
7
8
9
10
11

Explanation:

• The user must enter the range’s top limit.
• This value is supplied to the recursive function as an argument.
• The recursive function’s basic case is that number should always be bigger than zero.
• If the number is greater than zero, the function is called again with the argument set to the number minus one.
• The number has been printed.
• The recursion will continue until the number is less than zero.

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Recursion in Python:

When a function calls itself and loops until it reaches the intended end state, this is referred to as recursion. It is based on the mathematics idea of recursive definitions, which define elements in a set in terms of other members in the set.

Each recursive implementation contains a base case in which the desired state is reached, and a recursive case in which the desired state is not reached and the function enters another recursive phase.

On each step, the behavior in the recursive situation before the recursive function call, the internal self-call, is repeated. Recursive structures are beneficial when a larger problem (the base case) can be solved by solving repeated subproblems (the recursive case) that incrementally advance the program to the base case.
It behaves similarly to for and while loops, with the exception that recursion moves closer to the desired condition, whereas for loops run a defined number of times and while loops run until the condition is no longer met.

In other words, recursion is declarative because you specify the desired state, whereas for/while loops are iterative because you provide the number of repeats.

Strings in Python:

A string is typically a piece of text (sequence of characters). To represent a string in Python, we use ” (double quotes) or ‘ (single quotes).

Examples:

Example1:

Input:

given string = "btechgeeksskeeghcetb"

Output:

The given string [ btechgeeksskeeghcetb ] is a palindrome

Example2:

Input:

given string = "aplussulpa"

Output:

The given string [ aplussulpa ] is a palindrome

Program to Check Whether a String is a Palindrome or not Using Recursion

Below are the ways to Check Whether a String is a Palindrome or not using the recursive approach in Python:

• Using Recursion(Static Input)
• Using Recursion(User Input)

1)Using Recursion (Static Input)

Approach:

• Give some string as static input and store it in a variable.
• Pass the string to a recursive function checkPalindromeRecursion function as an argument.
• Calculate the length of the string using the len() function.
• If the length of the string is less than 1, the function returns True.
• If the end letter is the same as the initial letter, execute the function recursively with the parameter as the sliced list with the first and last characters deleted, otherwise return False.
• Use an if statement to determine whether the given string is True or False and then print the result.
• If the function returns true then the given string is a palindrome.
• Else the given string is not a palindrome.
• The exit of the program.

Below is the implementation:

# function which checks the given string is palindrome or not using recursion
# if th given string is palindrome then it is true else the string is false.


def checkPalindromeRecursion(givenstr):
  # Calculate the length of the string using the len() function.
    stringLen = len(givenstr)
    # If the length of the string is less than 1, the function returns True.
    if stringLen < 1:
        return True
    else:
      # If the end letter is the same as the initial letter, execute the function
      # recursively with the parameter as the sliced list
      # with the first and last characters deleted, otherwise return False.
      # Use an if statement to determine whether the given string is
      # True or False and then print the result.
        if givenstr[0] == givenstr[-1]:
            return checkPalindromeRecursion(givenstr[1:-1])
        else:
            return False


# Give some string as static input and store it in a variable.
given_str = 'btechgeeksskeeghcetb'
# Pass the string to a recursive function checkPalindromeRecursion function as an argument.
# If the function returns true then the given string is a palindrome.
if(checkPalindromeRecursion(given_str)):
    print("The given string [", given_str, '] is a palindrome')
# Else the given string is not a palindrome.
else:
    print("The given string", given_str, 'is not a palindrome')

Output:

The given string [ btechgeeksskeeghcetb ] is a palindrome

2)Using Recursion (User Input)

Approach:

• Give some random string as user input using the input() function and store it in a variable.
• Pass the string to a recursive function checkPalindromeRecursion function as an argument.
• Calculate the length of the string using the len() function.
• If the length of the string is less than 1, the function returns True.
• If the end letter is the same as the initial letter, execute the function recursively with the parameter as the sliced list with the first and last characters deleted, otherwise return False.
• Use an if statement to determine whether the given string is True or False and then print the result.
• If the function returns true then the given string is a palindrome.
• Else the given string is not a palindrome.
• The exit of the program.

Below is the implementation:

# function which checks the given string is palindrome or not using recursion
# if th given string is palindrome then it is true else the string is false.


def checkPalindromeRecursion(givenstr):
  # Calculate the length of the string using the len() function.
    stringLen = len(givenstr)
    # If the length of the string is less than 1, the function returns True.
    if stringLen < 1:
        return True
    else:
      # If the end letter is the same as the initial letter, execute the function
      # recursively with the parameter as the sliced list
      # with the first and last characters deleted, otherwise return False.
      # Use an if statement to determine whether the given string is
      # True or False and then print the result.
        if givenstr[0] == givenstr[-1]:
            return checkPalindromeRecursion(givenstr[1:-1])
        else:
            return False


# Give some random string as user input using the input()
# function and store it in a variable.
given_str = input('Enter some random string = ')
# Pass the string to a recursive function checkPalindromeRecursion function as an argument.
# If the function returns true then the given string is a palindrome.
if(checkPalindromeRecursion(given_str)):
    print("The given string [", given_str, '] is a palindrome')
# Else the given string is not a palindrome.
else:
    print("The given string", given_str, 'is not a palindrome')

Output:

Enter some random string = aplussulpa
The given string [ aplussulpa ] is a palindrome

Explanation:

• A string must be entered by the user.
• A recursive function gets the string as an argument.
• If the length of the string is less than one, the function returns True.
• If the end letter is the same as the initial letter, the function is repeated recursively with the argument as the sliced list with the first and last characters removed, otherwise, false is returned.
• The if statement is used to determine whether the returned value is True or False, and the result is printed.

Related Programs:

• Python Program to Find the Product of two Numbers Using Recursion
• Python Program to Find if a Number is Prime or Not Prime Using Recursion
• Python Program to Find the Power of a Number Using Recursion
• Python Program to Find the LCM of Two Numbers Using Recursion
• Python Program to Find the Length of a List Using Recursion
• Python Program to Reverse a String Using Recursion

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Python Program to Print the pattern of an Inverted Star: Given a number, the task is to print an Inverted Star Pattern in Python. In our python programming articles, you can also learn how to print a program of Inverted pyramid pattern and print inverted pyramid star pattern in python language.

Let’s see the examples of python program to print inverted star pattern from here

Example1:

Input:

given rows = 8

Output:

********
 *******
  ******
   *****
    ****
     ***
      **
       *

Example2:

Input:

given rows=10

Output:

**********
 *********
  ********
   *******
    ******
     *****
      ****
       ***
        **
         *

Here is the program to print Inverted Star Pattern:

# python 3 code to print inverted star
# pattern 
  
# n is the number of rows in which
# star is going to be printed.
n=11
  
# i is going to be enabled to
# range between n-i t 0 with a
# decrement of 1 with each iteration.
# and in print function, for each iteration,
# ” ” is multiplied with n-i and ‘*’ is
# multiplied with i to create correct
# space before of the stars.
for i in range (n, 0, -1):
    print((n-i) * ' ' + i * '*')

Program to Print an Inverted Star Pattern in Python

Below are the ways to print an Inverted Star Pattern in  Python :

• Using for loop printing the inverted star pattern in Python (Static Input)
• Using for loop printing the inverted star pattern in Python (User Input)
• Using while loop printing the inverted star pattern in Python (Static Input)
• Using while loop printing the inverted star pattern in Python (User Input)
• Programs to print inverted half pyramid using *

Drive into Python Programming Examples and explore more instances related to python concepts so that you can become proficient in generating programs in Python Programming Language.

1)Using for loop printing the inverted star pattern in Python(Static Input)

Approach:

• Give the number as static and store it in a variable
• Use a for loop in which the value of k varies between n-1 and 0 and is decremented by one with each iteration.
• Multiply empty spaces by n-i and ‘*’ by k then print both of them.
• Exit of program.

Below is the implementation:

# given number numb
numb = 8
# Use a for loop in which the value of k varies
# between n-1 and 0 and is decremented by one with each iteration.
for k in range(numb, 0, -1):
  # Multiply empty spaces by n-i and '*' by k then print both of them.
    print((numb-k) * ' ' + k * '*')

Output:

********
 *******
  ******
   *****
    ****
     ***
      **
       *

Explanation:

• Give the number as static and stored it in  a variable numb
• The for loop allows I to range between n-1 and 0, with each iteration decrementing by one.
• To maintain proper star spacing, ” ” is multiplied by n-i and ‘*’ is multiplied by I for each iteration.
• The requisite pattern has been printed.

2)Using for loop printing the inverted star pattern in Python(User Input)

Approach:

• Scan the given number using int(input()) and store it in a variable.
• Use a for loop in which the value of k varies between n-1 and 0 and is decremented by one with each iteration.
• Multiply empty spaces by n-i and ‘*’ by k then print both of them.
• Exit of program.

Below is the implementation:

# given number numb
numb = int(input("enter the number of rows required = "))
# Use a for loop in which the value of k varies
# between n-1 and 0 and is decremented by one with each iteration.
for k in range(numb, 0, -1):
  # Multiply empty spaces by n-i and '*' by k then print both of them.
    print((numb-k) * ' ' + k * '*')

Output:

enter the number of rows required = 10
**********
 *********
  ********
   *******
    ******
     *****
      ****
       ***
        **
         *

3)Using while loop printing the inverted star pattern in Python(Static Input)

Approach:

• Give the number as static and store it in a variable
• Using while loop iterate till number is greater than 0.
• Multiply empty spaces by tem-i and ‘*’ by numb then print both of them.
• Decrement the number by 1.
• The Exit of the program.

Below is the implementation:

# given number numb
numb = 10
# Make a duplicate of the integer by storing it in a variable
tem = numb
# Use a for loop in which the value of k varies
# between n-1 and 0 and is decremented by one with each iteration.
while(numb > 0):
  # Multiply empty spaces by n-i and '*' by k then print both of them.
    print((tem-numb) * ' ' + numb * '*')
    # decrement the number by 1
    numb = numb-1

Output:

**********
 *********
  ********
   *******
    ******
     *****
      ****
       ***
        **
         *

4)Using while loop printing the inverted star pattern in Python(User Input)

Approach:

• Scan the given number using int(input()) and store it in a variable.
• Using while loop iterate till number is greater than 0.
• Multiply empty spaces by tem-i and ‘*’ by numb then print both of them.
• Decrement the number by 1.
• Exit of program.

Below is the implementation:

# given number numb
numb = int(input("enter the number of rows required = "))
# Make a duplicate of the integer by storing it in a variable
tem = numb
# Use a for loop in which the value of k varies
# between n-1 and 0 and is decremented by one with each iteration.
while(numb > 0):
  # Multiply empty spaces by n-i and '*' by k then print both of them.
    print((tem-numb) * ' ' + numb * '*')
    # decrement the number by 1
    numb = numb-1

Output:

enter the number of rows required = 10
**********
 *********
  ********
   *******
    ******
     *****
      ****
       ***
        **
         *

Programs to print inverted half pyramid using *

This instance is similar to an upright pyramid but that here we begin from the total number of rows and in each iteration, we decrease the number of rows by 1.

Source Code:

rows = int(input("Enter number of rows: "))

for i in range(rows, 0, -1):
    for j in range(0, i):
        print("* ", end=" ")
    
    print("\n")

output: 

* * * * *
* * * *
* * *
* *
*

Related Programs:

• Python Program to Form an Integer that has the Number of Digits at Ten’s Place and the Least Significant Digit of the Entered Integer at One’s Place
• Python Program to Generate a Dictionary that Contains Numbers (between 1 and n) in the Form (x, x*x).
• Python Program to Form a New String Made of the First 2 and Last 2 characters From a Given String
• Python Program to Form a New String where the First Character and the Last Character have been Exchanged
• Python Program to Solve Quadratic Equation

Interested in programming and want to excel in it by choosing the short ways. Then, practicing with the available Java Program list is mandatory.

Dictionaries in Python:

Dictionary is a mutable built-in Python Data Structure. It is conceptually related to List, Set, and Tuples. It is, however, indexed by keys rather than a sequence of numbers and can be thought of as associative arrays. On a high level, it consists of a key and its associated value. The Dictionary class in Python represents a hash-table implementation.

Given a string , the task is to create a Python program for creating a dictionary with the Key as the first character and the Value as words beginning with that character.

Examples:

Example1:

Input:

given string = "hello this is btechgeeks online programming platform to read the coding articles specially python language"

Output:

h ::: ['hello']
t ::: ['this', 'to', 'the']
i ::: ['is']
b ::: ['btechgeeks']
o ::: ['online']
p ::: ['programming', 'platform', 'python']
r ::: ['read']
c ::: ['coding']
a ::: ['articles']
s ::: ['specially']
l ::: ['language']

Example2:

Input:

given string = "this is btechgeeks today is monday and tomorrow is sunday sun sets in the east "

Output:

t ::: ['this', 'today', 'tomorrow', 'the']
i ::: ['is', 'in']
b ::: ['btechgeeks']
m ::: ['monday']
a ::: ['and']
s ::: ['sunday', 'sun', 'sets']
e ::: ['east']

Program to Create a Dictionary with Key as First Character and Value as Words Starting with that Character

Below are the ways to create a Python program for creating a dictionary with the Key as the first character and the Value as words beginning with that character.

• Using indexing, append ,items() function (Static Input)
• Using indexing, append ,items() function (User Input)

Drive into Python Programming Examples and explore more instances related to python concepts so that you can become proficient in generating programs in Python Programming Language.

1)Using indexing, append ,items() function (Static Input)

Approach:

• Give the string as static input .
• Declare a dictionary which is empty using {} or dict()
• Divide the string into words using split() and save them in a list.
• Using a for loop and an if statement, determine whether the word already exists as a key in the dictionary.
• If it is not present, use the letter of the word as the key and the word as the value to create a sublist in the list and append it to it.
• If it is present, add the word to the associated sublist as the value.
• The resultant dictionary will be printed.
• Exit of Program

Below is the implementation:

# given string
given_string = "hello this is btechgeeks online programming platform to read the coding articles specially python language"
# Split the given string into words using split() function
# Convert this into list using list() function.
listString = given_string.split()
# Declare a dictionary which is empty using {} or dict()
resultdict = {}
# Traverse the list String
for stringword in listString:
  # checking if the first character of the word exists in dictionary resultdict keys or not
    if(stringword[0] not in resultdict.keys()):
        resultdict[stringword[0]] = []
        # adding this character to the resultdict
        resultdict[stringword[0]].append(stringword)
    else:
      # If it is present, add the word to the associated sublist as the value.
        if(stringword not in resultdict[stringword[0]]):
            resultdict[stringword[0]].append(stringword)
for key, value in resultdict.items():
    print(key, ":::", value)

Output:

h ::: ['hello']
t ::: ['this', 'to', 'the']
i ::: ['is']
b ::: ['btechgeeks']
o ::: ['online']
p ::: ['programming', 'platform', 'python']
r ::: ['read']
c ::: ['coding']
a ::: ['articles']
s ::: ['specially']
l ::: ['language']

Explanation:

• A string must be entered by the user or give input as static and saved in a variable.
• It is declared that the dictionary is empty.
• The string is split down into words and kept in a list.
• To iterate through the words in the list, a for loop is utilised.
• An if statement is used to determine whether a word already exists as a key in the dictionary.
• If it is not present, the letter of the word is used as the key and the word as the value, and they are appended to the list’s sublist.
• If it is present, the word is added to the associated sublist as a value.
• The final dictionary is printed

2)Using indexing, append ,items() function (User Input)

Approach:

• Scan the given string using input() function.
• Declare a dictionary which is empty using {} or dict()
• Divide the string into words using split() and save them in a list.
• Using a for loop and an if statement, determine whether the word already exists as a key in the dictionary.
• If it is not present, use the letter of the word as the key and the word as the value to create a sublist in the list and append it to it.
• If it is present, add the word to the associated sublist as the value.
• The resultant dictionary will be printed.
• Exit of Program

Below is the implementation:

# Scanning the given string
given_string = input("Enter some random string separated by spaces = ")
# Split the given string into words using split() function
# Convert this into list using list() function.
listString = given_string.split()
# Declare a dictionary which is empty using {} or dict()
resultdict = {}
# Traverse the list String
for stringword in listString:
  # checking if the first character of the word exists in dictionary resultdict keys or not
    if(stringword[0] not in resultdict.keys()):
        resultdict[stringword[0]] = []
        # adding this character to the resultdict
        resultdict[stringword[0]].append(stringword)
    else:
      # If it is present, add the word to the associated sublist as the value.
        if(stringword not in resultdict[stringword[0]]):
            resultdict[stringword[0]].append(stringword)
for key, value in resultdict.items():
    print(key, ":::", value)

Output:

Enter some random string separated by spaces = this is btechgeeks today is monday and tomorrow is sunday sun sets in the east
t ::: ['this', 'today', 'tomorrow', 'the']
i ::: ['is', 'in']
b ::: ['btechgeeks']
m ::: ['monday']
a ::: ['and']
s ::: ['sunday', 'sun', 'sets']
e ::: ['east']

Related Programs:

• Python Program to Count the Frequency of Words Appearing in a String Using a Dictionary
• Python Program to Map Two Lists into a Dictionary
• Python Program to Generate a Dictionary that Contains Numbers (between 1 and n) in the Form (x, x*x).
• Python Program to Add a Key, Value Pair to the Dictionary
• Python Program to Sum All the Items in a Dictionary